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Arisa [49]
3 years ago
5

Convert the following 1) 52.1g NaNO3 To moles

Chemistry
1 answer:
ivann1987 [24]3 years ago
5 0

Answer:

0.6129796138981438

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What is the value for ∆Soreaction for the following reaction, given the standard entropy values? 2 Al (s) + 3Cl2(g) 2AlCl3(s)
svetlana [45]
2Al(s) + 3Cl₂ → 2AlCl₃

Forming the equation:
2(28) + 3(223) = ΔH + 2(111)
ΔH = 503 kJ

Writing this outside of the reaction equation:
ΔH = -503 kJ

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Which fossil fuel is the remains of ancient plants?<br> A. Coal<br> B. Petroleum<br> C. Natural Gas
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A. Coal

Others are animal remains

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3 years ago
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Nitrogen gas in an expandable container is cooled from 45.0 C to 12.3 C with the pressure held constant at 2.58 ∗ 105 Pa. The to
Tresset [83]

Answer:

The number of moles of the gas is: -27.14 mole

the charge in internal energy of the gas is -1.84 × 10⁴ J.

The work done by the gas is 4.42 × 10⁴ J

The heat liberated by the gas for the same temperature change while the volume was constant and is same as the change in internal energy.

As such ; Q = -1.84 × 10⁴ J.

Explanation:

The expression for the number of moles of a gas at constant pressure is as follows:

\mathbf{n = \frac{Q}{Cp \Delta T}}

\mathbf{n = \frac{Q}{Cp (T_2-T_1)}}

where ;

C_p is the specific heat at constant pressure of Nitrogen gas which is = 29.07 J/mol/K

Since heat is liberated from the gas ; then:

n = \dfrac{-2.58*10^4 }{29.07(45-12.3)}

n = -27.14 mole

The number of moles of the gas is: -27.14 mole

b) The expression to be used in order to determine the change internal energy is:

dU = nCv \Delta T

where ;

n= 27.14 mole

Cv = specific heat at constant volume of Nitrogen gas = 20.76 J/mol/K

ΔT = (12.3-45)

So;

dU = (27.14)(20.76)(12.3-45)

dU = 563.426(-32.7)

dU = -18424.04328

dU = -1.84 × 10⁴ J

Thus; the charge in internal energy of the gas is -1.84 × 10⁴ J.

c)  The workdone by the gas can be calculated as;

W = Q - ΔU

W = 2.58 × 10⁴ J - (-1.84 × 10⁴ J )

W = 2.58  × 10⁴ J + 1.84  × 10⁴ J

W = 4.42 × 10⁴ J

The work done by the gas is 4.42 × 10⁴ J

d) The expression to calculated the work done is given as:

W = pdV

since the volume is given as constant ; then dV = 0

so;

W = p(0)

W = 0

Replacing 0 for W in the equation W = Q - Δ U

0 = Q - ΔU

-Q = - ΔU

Q = ΔU

Thus , the heat liberated by the gas for the same temperature change while the volume was constant and is same as the change in internal energy.

As such ; Q = -1.84 × 10⁴ J.

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3 years ago
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If the copper is drawn into wire whose diameter is 8.00 mm, how many feet of copper can be obtained from the ingot? the density
vampirchik [111]

Answer: 2369.84c

Explanation:

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