1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Sladkaya [172]
4 years ago
6

One of the questions in the Pew Internet & American Life Project asked adults if they used the Internet at least occasionall

y (Pew website, October 23, 2012). The results showed that 454 out of 478 adults aged 18 - 29 answered Yes; 741 out of 833 adults aged 30 – 49 answered Yes; 1058 out of 1644 adults aged 50 and over answered Yes.
Round your answers to four decimal places.
a. Develop a point estimate of the proportion of adults aged 18 – 29 who use the Internet.
b. Develop a point estimate of the proportion of adults aged 30 – 49 who use the Internet.
c. Develop a point estimate of the proportion of adults aged 50 and over who use the Internet.
d. Suppose your target population of interest is that of all adults (18 years of age and over). Develop an estimate of the proportion of that population who use the Internet.
Business
1 answer:
g100num [7]4 years ago
4 0

Answer:

Explanation:

S/N   Age range       Adult Population       Population Internet Users

A       18   -    29                 478                                 454

B       30   -    49                833                                 741

C       50 and above         1644                                1058

             Total                     2955                               2253

a) Let E = Estimate proportion and A = Internet users

Hence, n(E) = 478 and n(A) = 454

∴ Probability of Internet users (18 - 29), P(A) = n(A)/n(E) = 454/478 = 0.9498 (94.98%)

b) n(E) = 833 and n(B) = 741

∴ Probability of Internet users (30 - 49), P(B) = n(A)/n(E) = 741/833 = 0.8896 (88.96%)

c) n(E) = 1644 and n(C) = 1058

∴ Probability of Internet users (50 and above), P(C) = n(C)/n(E) = 1058/1644 = 0.6436 (64.36%)

d) Let Et = Total estimate proportion

Hence, n(Et) = 2955 and n(A) = 454

∴ Probability of 18 - 29 age range using Internet overall Pt(A) = n(A)/n(Et) = 454/2955 = 0.1536 (15.36%)

You might be interested in
A strategy is: Multiple Choice an action plan to maximize rewards in the current period in return for big risks. a procedure for
Strike441 [17]

Answer:

An action plan to achieve specific long term goals and objectives. based on the plans formed later resources are allocated. But initially long term goals and objectives are to be framed which is the main objective of strategic planning.

8 0
3 years ago
Based on market values, Gubler's Gym has an equity multiplier of 1.46 times. Shareholders require a return of 10.91 percent on t
rewona [7]

Answer:

The answer is "5.4% and 15,23,500".

Explanation:

Calculating the capital cost:

=(1-\frac{1}{1.46})\times 10.91\% \times (1-39\%)+(\frac{1}{1.46})\times 4.84\% \\\\=(\frac{1.46-1}{1.46})\times \frac{10.91}{100} \times (\frac{100-39}{100})+(\frac{1}{1.46})\times \frac{4.84}{100} \\\\ =(\frac{0.46}{1.46})\times \frac{10.91}{100} \times (\frac{61}{100})+(\frac{1}{1.46})\times \frac{4.84}{100} \\\\=\frac{306.1346}{14600}+\frac{4.84}{146} \\\\=  0.021+0.033 \\\\ =0.054\\\\= 5.4\%

Maximum amount to be spent

=\frac{277,000\times 100 }{5.4} \times (1-\frac{1}{(1.054)^7})\\\\=\frac{277,000\times 100 }{5.4} \times (1-\frac{1}{1.44})\\\\=\frac{277,000\times 100 }{5.4} \times (1-0.7)\\\\=277,000 \times 100\times 0.055\\\\=\$15,23,500\\

6 0
3 years ago
What is a foreign exchange rate?
ziro4ka [17]
Difference between the Us Dollar. 1 US dollar is .86 Euro
7 0
3 years ago
Read 2 more answers
Downs Tax Planning Service bought communications equipment for $9,600 on January 1, 2017. It has an estimated useful life of fiv
MaRussiya [10]

Answer:

$960

Explanation:

For computing the accumulated depreciation, first we have to compute the depreciation expense which is shown below:

= (Original cost - residual value) ÷ (useful life)

= ($9,600 - $0) ÷ (5 years)

= ($9,600) ÷ (5 years)  

= $1,920

This is a full year depreciation but we have to find out for June 30,2017 i.e 6 months

= $1,920 ÷ 12 months × 6 months

= $960

The same is recorded as an accumulated depreciation

3 0
3 years ago
At the price of $5 per pack of batteries, Duracell sells 10,000 packs of batteries and Energizer sells 15,000 packs of batteries
Verdich [7]

Answer:

28,000

Explanation:

To get this answer you have to assume perfect competition scenario, since in this case supply = demand. In this case:

At $7,5

Energizer sells 16,000 => Supply Energizer = 16,000

Duracell sells 12,000 => Supply Duracell = 12,000

Total Supply = 16,000+12,000

6 0
3 years ago
Other questions:
  • A company issued a purchase order on December 15, year 1, for a piece of capital equipment that costs $100,000. The capital equi
    9·1 answer
  • What is the consistent finding regarding age identity of 60- to 75-year-olds?
    11·1 answer
  • If a department that uses process costing starts the reporting period with 100,000 physical units that were 20% complete with re
    7·1 answer
  • The following events occurred for Favata Company: Received $16,000 cash from owners and issued stock to them. Borrowed $13,000 c
    6·1 answer
  • Which of these careers are examples of marketing occupations? Select all that apply. (2 points)
    9·1 answer
  • Productivity is the
    15·1 answer
  • The unemployment rate in the United States is usually​ ________ than the unemployment rates in most other​ high-income countries
    12·1 answer
  • In a proposal to install and monitor a security system statements such as "our company has over 25 years of experience" should a
    13·1 answer
  • Which stage of the money laundering process occurs when funds gained from criminal activity enter the financial institution?.
    13·1 answer
  • On January 1 of this year, Barnett Corporation sold bonds with a face value of $ 500,000 and a coupon rate of 7 percent. The bon
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!