This is the concept of algebra; given that the height of the house at time t is given by:
h(t)=<span> 400 − 39t − 157e−t/4
the velocity of the house is given by:
dh/dt
velocity of our object is:
dh/dt=-39+1/4*157e^-(t/4)
=-39+157/4 e^(-t/4)
thus the velocity at h=0 will be as follows:
at h=0, the value of t will be:
0=400-39t-157e^(-t/4)
solving for t we get:
t=-5.4 or t=10.1
since we don't have negative time, t=10.1
thus the velocity at this point will be:
dh/dt=-38+1/4*157e^(-10.1/4)
=-38.86 sec
this means that the object dropped by a velocity of 38.86 sec</span>
Step-by-step explanation:
b and c
...................
Answer:
0.77
Step-by-step explanation:
From the information given:
The breakdown time (a)= 3 hours
The breakdown rate (λ) = 1/a = 1/3
Average flow time in the system (W) = 2.305 hours
For the entire system;
The average down machines L = Wλ
= 2.305 × (1/3)
= 0.77
The answer is literally-5.7
Answer:
-12
Step-by-step explanation:
Use Order of Operations BPEMDAS:
-2 - [-3 + 7 + 6]
-2 - [4 + 6]
-2 - 10
-12