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slega [8]
3 years ago
13

In the triangle shown, what is the value of x

Mathematics
1 answer:
Anuta_ua [19.1K]3 years ago
7 0

Answer:

b 4 sqrt(2) cm

Step-by-step explanation:

Since this is a right triangle, we can use the Pythagorean theorem

a^2 + b^2 = c^2, where a and b are the legs

x^2 + x^2 = 8^2

2x^2 = 62

Divide each side by 2

2x^2/2 = 64/2

x^2 =32

Take the square root of each side

sqrt(x^2) = sqrt(32)

x = sqrt(16*2)

We know that sqrt(a*b)= sqrt(a) sqrt(b)

x = sqrt(16) sqrt(2)

x = 4sqrt(2)

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