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Reptile [31]
3 years ago
15

When a 2.50 kg object is hung vertically on a certain light spring described by hookes law the spring stretches 2.76 cm.

Physics
1 answer:
Readme [11.4K]3 years ago
8 0
F=K*X,
F=M*a 

M*a=K*X

2.5*9.81=K*0.0276

24.525=K*0.0276

24.525/0.0276=K

K= 888.6 N/m ---- force constant 

assuming 2.5 refers to the new extension, just divide F/ 0.025
to get

981N/m 


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8 0
2 years ago
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3 0
3 years ago
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