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nata0808 [166]
3 years ago
12

Steve just completed a woodworking project. now he wants to put a fine finish on his work

Physics
1 answer:
vesna_86 [32]3 years ago
8 0
Pad sander I think I’m not positive tho
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A 1.5 kg ball pushed with a force of 13.5 N accelerates to the left. What is the acceleration of the ball?​
GarryVolchara [31]

Explanation:

F= ma

13.5 =1.5a

1.5a/1.5 =13.5/1.5

a= 9 m/s^2

4 0
3 years ago
Which three metals are in the third period (row) of the periodic table?
Anettt [7]
Sodium, magnesium, and aluminum! 
6 0
3 years ago
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2 types of energy transformations that take place in a race car during a race?​
vichka [17]

Answer:

Explanation:

Chemical to thermal as fuel is burned

Thermal to kinetic as the hot gasses push on pistons

4 0
2 years ago
The electric field 14.0 cm from the surface of a copper ball of radius 2.0 cm is directed toward the ball's center and has magni
Marina CMI [18]

Answer:

Q = - 256 X 10⁻⁷ C .

Explanation:

Electric field due to a charge Q at a distance d from the center is given by the expression

E = k Q /d² Where k is a constant and it is equal to 9 x 10⁹

Put the given value in the equation

9 x 10² = \frac{9\times10^9\times Q}{(14+2)^2\times10^{-4}}

Q = \frac{9\times16^2\times10^{-2}}{9\times10^9}

Q = - 256 X 10⁻⁷ C .

It will be negative in nature as the field is directed towards the center.

5 0
3 years ago
Help meh in this question​
V125BC [204]

  • Radius=r=R_o/2
  • angular velocity=w=v_o
  • mass=m

We know

\boxed{\sf K.E=\dfrac{1}{2}mv^2}

For Rotational motion

\boxed{\sf v=r\omega}.

Putting value

\\ \qquad\quad\sf{:}\dashrightarrow K.E=\dfrac{1}{2}m(r\omega)^2

\\ \qquad\quad\sf{:}\dashrightarrow K.E=\dfrac{1}{2}mr^2\omega^2

\\ \qquad\quad\sf{:}\dashrightarrow K.E=\dfrac{1}{2}m\left(\dfrac{R_o}{2}\right)^2v_o^2

\\ \qquad\quad\sf{:}\dashrightarrow K.E=\dfrac{1}{4}mv_o^2

7 0
2 years ago
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