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sammy [17]
3 years ago
14

What do you mean by shearing stress??​

Physics
2 answers:
lord [1]3 years ago
8 0

Answer:

Shear stress, force tending to cause deformation of a material by slippage along a plane or planes parallel to the imposed stress. The resultant shear is of great importance in nature, being intimately related to the downslope movement of earth materials and to earthquakes.

Ivahew [28]3 years ago
6 0

Answer:

The process of removing of wool from sheep is called shearing.

Explanation:

so it means to remove stress

hope it helps

it is what i can grasp from your question

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A negative charge of 2 C and a positive charge of 3 C are separated by 80 m. What is the force between the two charges?
Zigmanuir [339]

Answer:

6

Explanation: i looked this up.

8 0
3 years ago
Resolving power of a telescope whose objective lens has diameter 1.22m for a wavelength 4000 Å.​
Mamont248 [21]

\sf \huge \purple{ Answer : - }

Diameter of objective lens = 1.22m

Wavelength of light = 4000Å

We have to find resolving power of telescope ..

★ Resolving power of telescope is given by

RP = D/1.22λ

  • D denotes diameter of lens
  • λ denotes wavelength of light

RP = D/1.22λ

RP = (1.22×10⁷)/(1.22×4)

RP = 0.25 × 10⁷

RP = 2.5 × 10⁶

★ Resolving power of microscope is given by

RP = 2μsinθ/λ

5 0
3 years ago
Problems related to radiation. (a) The temperature of the Sun’s photosphere is 5700 K. Assume it is a blackbody. What is the pea
sineoko [7]

Answer:

a) λ = 5,084 10⁻⁷ m , b)  P = 3.63 10²⁶ W , c)  P = 5.8 10²⁷ W and d)  λ = 2.54 10⁻⁷ m

Explanation:

a) The maximum emission of the sun can be calculated using the Win equation

     λ T = 2,898 10⁻³ m.K

     λ = 2,898 10⁻³ / T

     λ = 2,898 10⁻³ / 5700

     λ = 5,084 10⁻⁷ m

     λ = 5,084 10⁻⁷ m (1 10⁹ nm / 1m) =

     λ = 5,084 10² nm = 508.4 nm

      photon in the visible range

b) The emission of the Sun, is described by the Stefan equation

     P = σ A e T⁴

Where σ is the Stefan-Boltzmann constant that vslue is  5,670 10-8 W/m²K⁴, A area of ​​the Sun, and e the emissivity that for a perfect black body is 1

In order to use this equation, we must calculate the area of ​​the sun, we consider it a perfect sphere

      r = 695,000 km (1000m / 1 km) = 6.95 10⁸ m

Area of ​​a sphere

     A = 4π R²

     A = 4π (6.95 10⁸8)²

     A = 6.07 10¹⁸ m²

     P = 5,670 10⁻⁸ 6.07 10¹⁸  1  5700⁴

     P = 3.63 10²⁶ W

c) The new temperature is double the previous one

    T = 2 To

Let's substitute in the formula and calculate

     P = σ A e (2To)⁴

     P = σ A e T⁴ 2⁴

     Po = σ A e T4 = 3.63 10 26 W

   

    P = 16 Po

    P= 16 (3.63 10²⁶)

    P = 5.8 10²⁷ W

d) Let's calculate the explicit value of the temperature and use the Win equation

    T = 2 5700

    T = 11400K

    λ = 2,898 10⁻³ / 11400

    λ = 2.54 10⁻⁷ m

    λ = 2.54 10²nm = 254 nm

photon in the UV range

5 0
3 years ago
A car speeds up from 13 m/s to 23 m/s in 30 seconds. What is the acceleration of the car?
ra1l [238]
Well, <span>v = u + a×t is the equation.</span>
<span>
v: final velocity, which is 23 m/s in this equation.</span>
<span>u: initialo velocity = 13 m/s </span>
<span>a: acceleration = ? </span>
<span>t: time = 30s 
</span>
Your equation would be...

<span>23 = 13 + a×30 </span>
<span>a = (23 - 13) / 30 </span>
<span>a = 1 / 3 </span>
<span>a = 0.333 m/s</span>
7 0
3 years ago
A 0.30 kg yo-yo consists of two solid disks of radius 5.10 cm joined together by a massless rod of radius 1.0 cm and a string wr
docker41 [41]

Answer:

0.70046 m/s²

2.732862 N

Explanation:

g = Acceleration due to gravity = 9.81 m/s²

m = Mass of yo-yo = 0.3 kg

R = Radius of rolling disk = 5.1 cm

r = Radius of rod = 1 cm

For a rolling disks the acceleration is given by

a=\frac{g}{1+\frac{R^2}{2r}}\\\Rightarrow a=\frac{9.81}{1+\frac{0.051^2}{2\times 0.01^2}}\\\Rightarrow a=0.70046\ m/s^2

The acceleration of the yo-yo is 0.70046 m/s²

The tension in the string will be

T=m(g-a)\\\Rightarrow T=0.3\times (9.81-0.70046)\\\Rightarrow T=2.732862\ N

The tension in the string is 2.732862 N

8 0
3 years ago
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