The cart's acceleration to the right after the mass is released is determined as 7.54 m/s².
<h3>
Acceleration of the cart</h3>
The acceleration of the cart is determined from the net force acting on the mass-cart system.
Upward force = Downward force
ma = mg
13a = 10(9.8)
13a = 98
a = 98/13
a = 7.54 m/s²
Thus, the cart's acceleration to the right after the mass is released is determined as 7.54 m/s².
Learn more about acceleration here: brainly.com/question/14344386
#SPJ1
Answer:
Refraction is the slowing down of light waves as they pass into a different medium and speeding as they pass out.
hope it helps. plz mark me as brainliest.
To find the Voltage, ( V ) [ V = I x R ] V (volts) = I (amps) x R (Ω)
To find the Current, ( I ) [ I = V ÷ R ] I (amps) = V (volts) ÷ R (Ω)
To find the Resistance, ( R ) [ R = V ÷ I ] R (Ω) = V (volts) ÷ I (amps)
To find the Power (P) [ P = V x I ] P (watts) = V (volts) x I (amps)
Answer:
<h3>3.33m/s</h3>
Explanation:
Using the law of conservation of momentum
m1u1 + m2u2 = (m1+m2)v
m1 and m2 are the masses of the object
u1 and u2 are the velocities
v is the final velocity
Given
m1 = 50g
u1 = 10m/s
m2 = 100g
u2 = 0m/s (stationary ball)
Required
Common velocity v
Substitute
50(10) + 100(0) = (50+100)v
500 = 150v
v = 500/150
v = 3.33m/s
Hence the velocity of each ball immediately after the collision is 3.33m/s
The gravity of Earth. 9.8 m/s^-2
