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GuDViN [60]
2 years ago
6

In the year 2081 in a shipping port on the moon, workers for Ore-Space, Inc., hoist a 500.0 kg hunk of anorthosite moon rock by

a chain. (Neglect the weight of the chain.) The block is initially accelerating at 4.0 m/s.
How much force is being exerted by the chain?
Physics
1 answer:
Naddik [55]2 years ago
7 0

Answer:

2,800 n

Explanation:

hope this helps, have a nice day/night! :D

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2. Fracture mechanics. A structural component in the form of a wide plate is to be fabricated from a steel alloy that has a plan
ikadub [295]

Answer:

the critical flaw is subject to detection since this value of ac (16.8 mm) is greater than the 3.0 mm resolution limit.  

Explanation:

This problem asks that we determine whether or not a critical flaw in a wide plate is subject to detection  given the limit of the flaw detection apparatus (3.0 mm), the value of KIc (98.9 MPa m), the design stress (sy/2 in which s y = 860 MPa), and Y = 1.0.

ac=1/\pi (\frac{Klc}{Ys} )^{2}\\ ac=1/\pi(\frac{98.9}{(1)(860/2)} )^{2}\\  ac=0.0168m\\ac=16.8mm

Therefore, the critical flaw is subject to detection since this value of ac (16.8 mm) is greater than the 3.0 mm resolution limit.  

5 0
3 years ago
On both sides.
goldenfox [79]

Answer:

please put pic of the questions

3 0
2 years ago
What si unit measures speed ?
dlinn [17]
Hmm doesnt soujd familiar
4 0
3 years ago
Kevin draws a figure that has 4 sides all sides have the same length his figure has no right angels what figure does he draw
Svetllana [295]
Diamond/ rhombus/ parallelogram
4 0
3 years ago
A child in a tree house uses a rope attached to a basket to lift a 24 N dog upward through a distance of 4.9 m into the house.
jenyasd209 [6]
<h3>Answer:</h3>

117.6 Joules

<h3>Explanation:</h3>

<u>We are given;</u>

  • Force of the dog is 24 N
  • Distance upward is 4.9 m

We are required to calculate the work done

  • Work done is the product of force and distance
  • That is; Work done = Force × distance
  • It is measured in Joules.

In this case;

Force applied is equivalent to the weight of the dog.

Work done = 24 N × 4.9 m

                  = 117.6 Joules

Hence, the work done in lifting the dog is 117.6 Joules

3 0
3 years ago
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