Answer:
Your number is (3 sqrt(2)) / sqrt(2) = 3, and is a rational number indeed. I don't know exactly how to interpret the rest of the question. If r is a positive rational number and p is some positive real number, then sqrt(r^2 p) / sqrt(p) is always rational, being equal r. Possibly your question refers to situtions in which sqrt(c) is not uniquely determined, as for c negative real number or complex non-real number. In those situations a discussion is necessary. Also, in general expressions the discussion is necesary, because the denominator must be different from 0, and so on.
Step-by-step explanation:
<h3>Answer:</h3>
Yes, ΔPʹQʹRʹ is a reflection of ΔPQR over the x-axis
<h3>Explanation:</h3>
The problem statement tells you the transformation is ...
... (x, y) → (x, -y)
Consider the two points (0, 1) and (0, -1). These points are chosen for your consideration because their y-coordinates have opposite signs—just like the points of the transformation above. They are equidistant from the x-axis, one above, and one below. Each is a <em>reflection</em> of the other across the x-axis.
Along with translation and rotation, <em>reflection</em> is a transformation that <em>does not change any distance or angle measures</em>. (That is why these transformations are all called "rigid" transformations: the size and shape of the transformed object do not change.)
An object that has the same length and angle measures before and after transformation <em>is congruent</em> to its transformed self.
So, ... ∆P'Q'R' is a reflection of ∆PQR over the x-axis, and is congruent to ∆PQR.
Answer:
30⁰ , 60⁰ , 90⁰
Step-by-step explanation:
Let the angles x , 2x , 3x
By angle sum property:
x + 2x + 3x = 180⁰
6x = 180⁰
x = 30⁰
Angles are : 30⁰ , 60⁰ , 90⁰
Answer:
1
Step-by-step explanation:
85 beads 3 bracelets
83 divided by 3 = 28.333
Rounded is 28 and adding the 0.333's you get
0.999.
0.99 is left over which rounds to 1 so I say 1 is left over
<u>im not a math whizz</u><u> but this seemed to make sense to me</u>
<u>so I hope this at least pushed you in the right direction :)</u>
