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qaws [65]
3 years ago
12

The original price of a jar of paint is$1.20 the store manager gets a 10 percent discount on orders of at least 50 jars of paint

.How much does the store manager pay fo 50 jars of paint.
Mathematics
1 answer:
sleet_krkn [62]3 years ago
4 0

Answer:

$54

Step-by-step explanation:

50 * $1.20 = $60

Before the discount, 50 jars cost $60.

Since the discount rate is 10%, he will pay only 90% of the price since 100% - 10% = 90%.

90% of $60 =

= 90% * $60

= 0.9 * $60

= $54

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14.45

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An airport limousine can accommodate up to four passengers on any one trip. The company will accept a maximum of six reservation
miss Akunina [59]

Answer:

a) 0.109375 = 0.109 to 3 d.p

b) 1.00 to 3 d.p

Step-by-step explanation:

Probability of someone that made a reservation not showing up = 50% = 0.5

Probability of someone that made a reservation showing up = 1 - 0.5 = 0.5

a) If six reservations are made, what is the probability that at least one individual with a reservation cannot be accommodated on the trip?

For this to happen, 5 or 6 people have to show up since the limousine can accommodate a maximum of 4 people

Let P(X=x) represent x people showing up

probability that at least one individual with a reservation cannot be accommodated on the trip = P(X = 5) + P(X = 6)

P(X = x) can be evaluated using binomial distribution formula

Binomial distribution function is represented by

P(X = x) = ⁿCₓ pˣ qⁿ⁻ˣ

n = total number of sample spaces = 6

x = Number of successes required = 5 or 6

p = probability of success = 0.5

q = probability of failure = 0.5

P(X = 5) = ⁶C₅ (0.5)⁵ (0.5)⁶⁻⁵ = 6(0.5)⁶ = 0.09375

P(X = 6) = ⁶C₆ (0.5)⁶ (0.5)⁶⁻⁶ = 1(0.5)⁶ = 0.015625

P(X=5) + P(X=6) = 0.09375 + 0.015625 = 0.109375

b) If six reservations are made, what is the expected number of available places when the limousine departs?

Probability of one person not showing up after reservation of a seat = 0.5

Expected number of people that do not show up = E(X) = Σ xᵢpᵢ

where xᵢ = each independent person,

pᵢ = probability of each independent person not showing up.

E(X) = 6(1×0.5) = 3

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So, expected number of unoccupied seats = 1

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