Answer:
No real solutions.
Step-by-step explanation:
729s^-5 = 729/s^5
729/s^5 = 3^2(1-s) = 9(1-s)
729=9(1-s)(s^5)
(1-s)(s^5)=81
s^5-s^6=81
Because 81 > 0 this means s^6 must be less than s^5. This is never possible as 6 is even so is always positive and is always greater in magnitude than s^5. The only time this isnt the case is when s is a decimal less than 1, but then the difference would be also less than 1 and not 81.
Two other examples of linear relationships are changes of units and finding the total cost for buying a given item x times.
<h3>
Other examples of linear relationships?</h3>
Two examples of linear relationships that are useful are:
Changes of units:
These ones are used to change between units that measure the same thing. For example, between kilometers and meters.
We know that:
1km = 1000m
So if we have a distance in kilometers x, the distance in meters y is given by:
y = 1000*x
This is a linear relationship.
Another example can be for costs, if we know that a single item costs a given quantity, let's say "a", then if we buy x of these items the total cost will be:
y = a*x
This is a linear relationship.
So linear relationships appear a lot in our life, and is really important to learn how to work with them.
If you want to learn more about linear relationships, you can read:
brainly.com/question/4025726
The expanded form could be:
.300+.060+.008
Use the first x then subtract the second x. then the y then the second y. yes it does matter because the numbers you subtract will add up to your answer
Answer:
multiply the numbers next to the variables by the given subtitution for the variable so 5 times 14 plus 36 and 6 times 12.5 minus 1 and 4 times 14 plus 50
Step-by-step explanation:
