All categories

3 years ago

Find the y-intercept of 91-90/19-16.

Mathematics

1 answer:

Elan Coil [88]3 years ago

7 0

Answer:

$91 - 90 \div 19 - 16$

You might be interested in

Find the measure of angle X in the triangle below.

daser333 [38]

Use the Law of Sines to solve.

24/Sin 67.38 = 26/Sin X
Cross multiply
26Sin 67.38 = 24SinX
Divide both sides by 24
(26Sin67.38)/24 = Sin X
Use Sin^-1 to find the angle measure.
Sin^-1 [(26Sin67.38)/24]
x = 89.92 degrees

5 0

3 years ago

Combine the following expressions. <img src="https://tex.z-dn.net/?f=a%20%5Csqrt%7Bx%7D%20%20%2B%20b%20%5Csqrt%7By%7D%20

Sedbober [7]

I hope this helps you

5 0

4 years ago

The diagram shows a vertical tower DC on a horizontal ground ABC.

sasho [114]

The measure of ABD=180°- 54°=26°
and then the measure of ADB= x
and x + 26° + 28°= 180°, sum of anlgle in a triagle property
it means x= 180°- 26-28=126°
application of sinus law in the triangle

sin 28 / BD = sin 126/ AD = sin 26/ 25 so we can deduce that

AD= 25sin126 / sin26= 46.12
let 's consider the triangle ADC, so for finding h, we have sin 28 = h / AD
and then h = AD x sin28=21.65

Calculate the height of the tower is 21.65

6 0

3 years ago

2 1/3 divided by y= -1.27272727 what does y equal

Semmy [17]

Answer:

-1.83337261989

Step-by-step explanation:

(2 1/3)/y=-1.272727

2 1/3 = -1.272727y

y=-1.83337261989

6 0

3 years ago

jay beats terry at table tennis 3 out of 5 games. what is the experimental probability that terry will win their next game

lozanna [386]

Answer:

The experimental probability that terry will win their next game is $\frac{2}{5}$

Step-by-step explanation:

While theoretical probability is the ratio of the number of favourable outcomes to the total number of outcomes, the experimental probability is the ratio of number of times the event is occurring to the total number of trials of the experiment.

Out of 5 games jay wins 3

Now the experimental probability that terry will win their next game

= 1 - Probability of Jay winning the game----------------------(1)

Probability of Jay winning the game = $\frac{\text{number of occurrences of the event}}{\text{total number of trials made}}$

=> $\frac{3}{5}$ ----------------------------------------------------(2)

Substituting (2) in (1)

=> 1 - $\frac{3}{5}$

=> $\frac{5-3}{5}$

=> $\frac{2}{5}$

6 0

3 years ago