64 = 2 ^6
16 = 2^4 =
2^ 6*(2x+4) = 2^4 * 5x
6(2x+4) = 20x
10/3 x = 2x +4
4/3 x = 4
x = 3
you can also use logarithms like so
(2x+4)ln64 = 5x ln16
ln64/ln16 = 3/2
3/2 * 2x + 3/2 * 4 = 5x
3x + 6 = 5x
2x = 6
x = 3
The equation relating this should be linear since the increase in amount earned is constant throughout which is $24 per hour. The equation is in the form:
y = mx + b
where,
y = earning
m = slope or earning per hour = $24
x = total number of hours
b = y intercept or initial earning upon visit = $45
Hence,
y = 24x + 45
Since we are working at two separate work sites, therefore each site we must earn 810/2 = 405
So when y = 405:
405 = 24x + 45
x = 15 hours
So you must work 15 hours at each site, 30 in total.
<span>Given, y^2 - 14y = -44
Add 44 to both sides of the equation
</span>y^2 - 14y + 44 = -44 + 44<span>
</span>y^2 - 14y + 44 = 0
Using the quadratic formula x = [-b ± √(b² - 4ac)]/2a
Where,
a = 1
b = -14
c = 44
x = [-b ± √(b² - 4ac)]/2a
x = [-(-14) ± √(-14² - 4(1)(44)]/2(1)
x = [14 ± √(196 - 176)]/2
x = [14 ± √20]/2
x = (14 + √20)/2 OR (14 - √20)/2
x = (14 + 4.472)/2 OR (14 - 4.472)/2
x = 18.472/2 OR 9.528/2
x = 9.236 OR 4.764
The solution set is {9.236, 4.764}
TO EXPRESS THE ANSWER IN RADICALS
x = [14 ± √20]/2
x = (14 + √20)/2 OR (14 - √20)/2
x = (14 + 2√5)/2 OR (14 - 2√5)/2
<span>x = 7+√5 OR 7-√5
</span>
The solution set is {7+√5, 7-√5}
Answer : option A
To find the range of scores that represents the middle 50 % of the student who took the test , we find inter quartile
Inter quartile range is the middle 50% of the given range of scores.
The difference between the upper quartile and lower quartile is the inter quartile that is middle 50%
From the diagram , we can see that
Upper quartile = 89
lower quartile = 65
So range is 65% to 89%
