All categories

3 years ago

Really need help with number 20

Mathematics

2 answers:

OverLord2011 [107]3 years ago

8 0

Your answer is going to be c

Bezzdna [24]3 years ago

8 0

Your answer is most likely C

You might be interested in

Solve for x 36x-6=16x+18x+2

Elodia [21]

Answer: X=4

Step-by-step explanation:

Pulling out like terms :

1.1 Pull out like factors :

2x - 8 = 2 • (x - 4)

Equation at the end of step 1 :

Step 2 :

Equations which are never true :

2.1 Solve : 2 = 0

This equation has no solution.

A a non-zero constant never equals zero.

Solving a Single Variable Equation :

2.2 Solve : x-4 = 0

Add 4 to both sides of the equation :

x = 4

One solution was found :

x = 4

7 0

3 years ago

What is the value of C in the matrix equation below?

lara [203]

Given:

The matrix equation is:

$\begin{bmatrix}-18&3&5\end{bmatrix}-C=\begin{bmatrix}-22&1&12\end{bmatrix}$

To find:

The value of matrix C.

Solution:

Let $A=\begin{bmatrix}-18&3&5\end{bmatrix},B=\begin{bmatrix}-22&1&12\end{bmatrix}$ . Then the given equation can be rewritten as

$A-C=B$

$-C=B-A$

$C=-(B-A)$

$C=A-B$

On substituting the values of the matrices, we get

$C=\begin{bmatrix}-18&3&5\end{bmatrix}-\begin{bmatrix}-22&1&12\end{bmatrix}$

$C=\begin{bmatrix}-18-(-22)&3-1&5-12\end{bmatrix}$

$C=\begin{bmatrix}-18+22&2&-7\end{bmatrix}$

$C=\begin{bmatrix}-4&2&-7\end{bmatrix}$

Therefore, the correct option is C.

6 0

3 years ago

Read 2 more answers

A circle is centered at (0,0) and has a radius of 2\sqrt{3}

VikaD [51]

Answer:

Outside of the circle

Step-by-step explanation:

First, find the equation of the circle by plugging in the center point and radius:

(x - h)² + (y - k)² = r²

(x - 0)² + (y - 0)² = ( $2\sqrt{3}$ )²

x² + y² = 12

Plug in point M to see where it lies:

x² + y² = 12

(-3)² + (2)² = 12

9 + 4 = 12

13 ≠ 12

Since this statement is false, point M lies outside of the circle.

5 0

3 years ago

2. Sam is climbing 2/3 meters every 1/3 of an hour. How many meters does

ICE Princess25 [194]

Answer:

2/9

Step-by-step explanation:

if u multiply 2/3 × 1/3 u get 2/9

4 0

3 years ago

The top and bottom margins of a poster are each 12 cm and the side margins are each 8 cm. The area of printed material on the po

grin007 [14]

Answer:

Dimensions of printed poster are

length is 32 cm

width is 48 cm

Step-by-step explanation:

Let's assume

length of printed poster is x cm

width of printed poster is y cm

now, we can find area of printed poster

so, area of printed poster is

$=xy$

we are given that area as 1536

so, we can set it to 1536

$xy=1536$

now, we can solve for y

$y=\frac{1536}{x}$

now, we are given

The top and bottom margins of a poster are each 12 cm and the side margins are each 8 cm

so, total area of poster is

$A=(8+x+8)\times (12+y+12)$

$A=(x+16)\times (y+24)$

now, we can plug back y

$A=(x+16)\times (\frac{1536}{x}+24)$

now, we have to minimize A

so, we will find derivative

$A'=\frac{d}{dx}\left(\left(x+16\right)\left(\frac{1536}{x}+24\right)\right)$

we can use product rule

$A'=\frac{d}{dx}\left(x+16\right)\left(\frac{1536}{x}+24\right)+\frac{d}{dx}\left(\frac{1536}{x}+24\right)\left(x+16\right)$

$=\frac{d}{dx}\left(x+16\right)\left(\frac{1536}{x}+24\right)+\frac{d}{dx}\left(\frac{1536}{x}+24\right)\left(x+16\right)$

now, we can simplify it

$A'=-\frac{24576}{x^2}+24$

now, we can set it to 0

and then we can solve for x

$A'=-\frac{24576}{x^2}+24=0$

$-\frac{24576}{x^2}x^2+24x^2=0\cdot \:x^2$

$-24576+24x^2=0$

$x=32,\:x=-32$

Since, x is dimension

and dimension can never be negative

so, we will only consider positive value

$x=32$

now, we can solve for y

$y=\frac{1536}{32}$

$y=48$

so, dimensions of printed poster are

length is 32 cm

width is 48 cm

5 0

3 years ago