Question

What is the value of z in the equation 2(4z − 3 − 1) = 166 − 46?

Answer 1

Refine $2(4z-3-1)$

$= 2(4z-4)$

Refine : $166 - 16 = 120$

therefore:

$2(z-4) = 120$

Divide both sides by  2 :

$\frac{2(z-4)}{2} = \frac{120}{2}$

$4z-4 = 60$

add 4  to both sides:

$4z-4+4 = 60+4$

$4z = 64$

Divide both sides by 4 :

$\frac{4z}{4} = \frac{64}{4}$

$z = 16$

hope this helps!

Answer 2

Solutions 

1) Simplify 4z−3−1 to 4z−4

2(4z−4)=166−46

2) Simplify 166−46 to 120

2(4z−4)=120

3) Divide the equation from both sides by 2

4z−4=120 ÷ 2

4) Simplify 120 ÷ 2 to 60

4z−4=60

5)  Add 4 to both sides

4z=60+4

6) Simplify 60+4 to 64

4z=64

7) Divide both sides by 4z=64 ÷ 4

8) Simplify 64 ÷ 4 to 16

z=16