<h2>
Explanation:</h2><h2>
</h2>
The figure to this problem is attached below. We know that angles ∠AEG and ∠GEC are supplementary, so:
∠AEG + ∠GEC = 180°
∠AEG = 8x°
∠GEC = (4x + 60)°
8x° + (4x + 60)° = 180°
(12x + 60)° = 180°
12x + 60 = 180
12x = 180 - 60
12x = 120
x = 10
∠AEG and ∠BEC are vertical angles, so they are congruent:
∠BEC = 8x°
∠BEC = 8(10)°
∠BEC = 80°
The equation of the line in its generic form is:
y = mx + b
Where,
m = (y2-y1) / (x2-x1)
For (-1, 3) and (0, 1):
We look for the value of m:
m = (1-3) / (0 - (- 1))
m = (- 2) / (0 + 1)
m = -2
We look for the value of b:
1 = m (0) + b
b = 1
The line is:
y = -2x + 1
For (1, 4) and (0, 2):
We look for the value of m:
m = (2-4) / (0-1)
m = (- 2) / (- 1)
m = 2
We look for the value of b:
2 = m (0) + b
b = 2
The line is:
y = 2x + 2
The system of equations is:
y = -2x + 1
y = 2x + 2
Answer:
the system has one solution
A, the answer is A, something to do with opposite angles being the same, so A because 127 + 127 = 254
In factorizing its 36 my dude. Im sure just took the test
I'm going to put this into vertex form, which is y=a(x-h)^2+k
To do this, you use completing the square. Start by subtracting 1 from each side
-1+y=x^2+2x
Then, divide b (2) by 2 and square it. Add that number to each side. (normally when you complete the square, you take out the gcf of the right side of the equation before you do this. Then, you would multiply (b/2)^2 by the gcf before adding it to the left side. Since there is no gcf, we do not have to worry about this)
2/2=1
1^2=1
-1+1+y=x^2+2x+1
Next, simplify the left side and factor the right side.
y=(x+1)^2
This is vertex form. a=1, h=-1, and k=0
The vertex is (h,k) so it is (-1,0)
hope this helps!
