of these layers of the atmosphere, has the greatest air pressure A. mesosphere B. stratosphere C. exosphere D. troposphere
2 answers:
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Answer:
S = 40.8m
Explanation:
<u>Given the following data;</u>
Initial velocity, u = 2m/s
Acceleration, a = 1.6m/s²
Time, t = 6secs
Required to find the displacement
Displacement, S = ?
The displacement of an object is given by the second equation of motion;
Where;
- S represents the displacement measured in meters.
- u represents the initial velocity measured in meters per seconds.
- t represents the time measured in seconds.
- a represents acceleration measured in meters per seconds square.
<em>Substituting into the equation, we have;</em>
S = 40.8m
<em>Therefore, the displacement of the skateboarder during this game is 40.8 meters. </em>
The work done by a gas during an isothermal process is given by:
(1)
where
n is the number of moles of the gas
R is the gas constant
T is the absolute temperature of the gas
is the ratio between the final volume and the initial volume of the gas
We need to calculate this ratio, and we can do it by using the gas pressure. In fact, for an isothermal process, Boyle's law states that the product between pressure and volume of the gas is constant:
which can be rewritten as
which is equivalent to
The problem says that the pressure of the gas is tripled, therefore the ratio between final and initial volume is:
Now we can use eq.(1) to calculate the work done by the gas. The absolute temperature is
The number of moles is n=2, therefore the work done is
And the work is negative, because it is done by the environment on the gas (the gas is compressed)
where
n is the number of moles of the gas
R is the gas constant
T is the absolute temperature of the gas
We need to calculate this ratio, and we can do it by using the gas pressure. In fact, for an isothermal process, Boyle's law states that the product between pressure and volume of the gas is constant:
which can be rewritten as
which is equivalent to
The problem says that the pressure of the gas is tripled, therefore the ratio between final and initial volume is:
Now we can use eq.(1) to calculate the work done by the gas. The absolute temperature is
The number of moles is n=2, therefore the work done is
And the work is negative, because it is done by the environment on the gas (the gas is compressed)