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adoni [48]
3 years ago
9

Which of thWhich of the following is a true statement?

Physics
2 answers:
Mars2501 [29]3 years ago
8 0

Answer:

B. Both electric fields and forces decrease in strength as the distance increases.

Explanation:

from the Coulomb's law

F=\frac{k q_{1} q_{2} }{r^{2}}

electrif field is also expressed as

F = qE., so

E = \frac{k q}{r^{2}}

it can seen that electric force and electric field and dependent on distance. that is inverse square of distance.

so, if the electric force and eletric field decreases in strength, it is because the distance of separation has increased.

IgorC [24]3 years ago
7 0

Answer:

B. Both electric fields and forces ...

Explanation:

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Howkim has two magnetic first he put gthem beside
andreyandreev [35.5K]
What does this mean ?
8 0
3 years ago
While running, a person dissipates about 0.60 J of mechanical energy per step per kilogram of body mass. If a 61 kg person devel
liraira [26]

Answer:

2.66m/s

Explanation:

information we have

power: 65W

work per step per kilogram: 0.60J

mass: 61kg

length of a running step: 1.5m

---------------

the formula for power is:

P=\frac{W}{t}

where W is the work and t is time.

time is also defined as: t=\frac{distance}{velocity}=\frac{d}{v}

so substituting this into the formula for power we get:

P=\frac{W*v}{d}

where v is the velocity we are looking for, d is the distance per step: d=1.5m, W is the work per step and P is power P=65W.

we know that the work per step per kilogram is:

0.60J

so to find the work per step of his whole body we need to multiply the 0.60J by the 61 kilograms of his mas:

W=0.60J*61kg\\W=36.6Jthis is the work per step of the person.

So now we can calculate the velocity using the formula for power

P=\frac{W*v}{d}

clearing for v:

v=\frac{P*d}{W}\\

and substituting known values:

v=\frac{(65W)(1.5m)}{36.6J}= 2.66m/s

6 0
3 years ago
PLEASE HELP IM CONFUSED
Fittoniya [83]

Sound waves can be used in a similar way to "see" things. After turning on a sound source, we can look at the pattern of reflected sound waves that bounce back to us. Our own ears and brain don't process sound into mental pictures.


3 0
3 years ago
how does the frequency of a radio wave compare to the frequency of the vibrating electrons that produce it?
HACTEHA [7]

Answer:

mass

Explanation:

3 0
3 years ago
A 873-kg (1930-lb) dragster, starting from rest completes a 401.4-m (0.2509-mile) run in 4.945 s. If the car had a constant acce
Delvig [45]

To solve this problem it is necessary to apply the kinematic equations of motion.

By definition we know that the position of a body is given by

x=x_0+v_0t+at^2

Where

x_0 = Initial position

v_0 = Initial velocity

a = Acceleration

t= time

And the velocity can be expressed as,

v_f = v_0 + at

Where,

v_f = Final velocity

For our case we have that there is neither initial position nor initial velocity, then

x= at^2

With our values we have x = 401.4m, t=4.945s, rearranging to find a,

a=\frac{x}{t^2}

a = \frac{ 401.4}{4.945^2}

a = 16.41m/s^2

Therefore the final velocity would be

v_f = v_0 + at

v_f = 0 + (16.41)(4.945)

v_f = 81.14m/s

Therefore the final velocity is 81.14m/s

8 0
3 years ago
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