Answer:
The magnitude of the magnetic torque on the coil is 1.98 A.m²
Explanation:
Magnitude of magnetic torque in a flat circular coil is given as;
τ = NIASinθ
where;
N is the number of turns of the coil
I is the current in the coil
A is the area of the coil
θ is the angle of inclination of the coil and magnetic field
Given'
Number of turns, N = 200
Current, I = 7.0 A
Angle of inclination, θ = 30°
Diameter, d = 6 cm = 0.06 m
A = πd²/4 = π(0.06)²/4 = 0.002828 m²
τ = NIASinθ
τ = 200 x 7 x 0.002828 x Sin30
τ = 1.98 A.m²
Therefore, the magnitude of the magnetic torque on the coil is 1.98 A.m²
As the satellite panels extend, the angular velocity decreases due to drag force, and hence it will cause a decrease in the angular momentum of the satellite.
<h3>
What is angular momentum?</h3>
Angular momentum is defined as the quantity of rotation of a body, which is the product of mass, velocity and radius.
L = mvr
L = mωr²
where;
- m is mass of the object
- v is velocity
- r is radius
- ω is angular velocity
As the satellite panels extend, the angular velocity decreases due to drag force, and hence it will cause a decrease in the angular momentum of the satellite.
Learn more about angular momentum here: brainly.com/question/4126751
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Answer:
1.55 N
Explanation:
Density = mass / volume
0.789 g/mL = m / 200.0 mL
m = 157.8 g
Weight = mass × acceleration due to gravity
W = (0.1578 kg) (9.8 m/s²)
W = 1.55 N
Answer:
The net torque is zero
Explanation:
Let's assume that the dipole is compose of two equal but oposite charges e, and it cam be represented by a rod with one end having a charge e and the other end with a charge of -e. Notice that the dipole is parallel to the electric field thus the force felt by both of the charges will be parallel to the electric field. This means that there will be no components of the forces that are perpendicular to the rod which is a requirement for it to have a torque.
Answer:
true
Explanation:
free fall is said to be the downward movement of an object under the force of gravity only
