By Newton's second law,
<em>n</em> + (-<em>w</em>) = 0
<em>p</em> + (-<em>f</em> ) = (20 kg) (2 m/s²)
where <em>n</em> is the magnitude of the normal force, <em>w</em> is the weight of the box, <em>p</em> is the magnitude of the applied force (<em>p</em> for <u>p</u>ush or <u>p</u>ull), and <em>f</em> is the magnitude of the friction force.
Calculate the weight of the box:
<em>w</em> = (20 kg) (9.80 m/s²) = 196 N
Then
<em>n</em> = <em>w</em> = 196 N
and
<em>f</em> = <em>µ</em> <em>n</em> = 0.5 (196 N) = 98 N
Now solve for <em>p</em> :
<em>p</em> - 98 N = 40 N
<em>p</em> = 138 N
Yes it is, I don't want to give a long explanation but I did a whole project on diatoms for biology last week because we were learning about protists. A protist is something that is unicellular (made up of one cell) and diatoms are unicellular organisms.
Answer:
M_e = 6.04 * 10^24 kg
Explanation:
Given:
- The time period of moon orbit T = 27.32 days
- Distance from center of earth to moon r = 238,910 miles
- The gravitational constant G = 6.67408 * 10^-11
Find:
- Determine the mass of the earth
Solution:
- The mass of earth as a function of time period T and radius of orbit r is related by an expression as follows:
M_e = (2*pi / T)^2 * (r^3 / G)
M_e = (2*pi / 27.32*24*60*60)^2 * (238910*1609 / 6.67408 *10^-11)
M_e = 6.04 * 10^24 kg
Two components (vertical and horizontal)
Answer:
Ay=v₂t + ½ gt² is the best choice to solve this problem.
The height of the cliff is = 176.4 meters.
Explanation:
Given,
initial velocity = 0m/s as it is dropped vertically
acceleration = g = 9.8 m/s²
time = 6s
Height =?
Using the equation Ay=v₂t + ½ gt², we can calculate Ay, which is the height.
So,
Ay=v₂t + ½ gt²
by substituting v, t, and g, we get:
Ay= 0 × 6 + ½ × 9.8 × 6²
Ay = 0 + 4.9 × 36
Ay = 176.4 m
