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2 years ago

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An object of mass 20kg is released from a height of 10 meters above the ground level. The kinetic energy of the the object just

before it hits the ground is _show that if a force applied at an angle ∅ with the horizontal direction, work done = FcosØ

1 answer:

Yuri [45]2 years ago

7 0

Answer:

The answer is the object weighs 5 so 3-5 is 2

Explanation:

I took this test

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2 years ago

The gravitational force between two objects is 2400 N. What will be the gravitational force between the objects if the mass of o

motikmotik

Answer:

4800N

Explanation:

Lets assume,

Mass of first object = m₁

Mass of second object = m₂

Distance between the two objects = r

Thus the force between the two objects will be

$F = \frac{G\times m_{1}\times m_{2}}{r^{2}}$

where, G = Universal gravitational constant

Given, F = 2400N

New mass of second object = 2m₂

Now, the force will be

$F_{2} = \frac{G\times m_{1}\times 2m_{2}}{r^{2}}$

$F_{2}= 2\frac{G\times m_{1}\times m_{2}}{r^{2}}$

$F_{2}= 2F$

$F_{2}= 2\times2400$

Thus, F₂ = 4800N

6 0

3 years ago

A shell is fired from the ground with an initial speed of 1.60 × 103 m/s (approximately five times the speed of sound) at an ini

Volgvan

Answer:

The horizontal range will be $2.55\times 10^5m$

Explanation:

We have given initial speed of the shell u = $1.6\times 10^3m/sec$

Angle of projection = 51°

Acceleration due to gravity $g=9.8m/sec^2$

We have to find maximum range

Horizontal range in projectile motion is given by

$R=\frac{u^2sin2\Theta }{g}=\frac{(1.60\times 10^3)^2sin(2\times 51^{\circ})}{9.81}=2.55\times 10^5m$

So the horizontal range will be $2.55\times 10^5m$

6 0

2 years ago