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Black_prince [1.1K]

4 years ago

13

Jayden sows pea seeds and watches them grow into seedlings. To better understand photosynthesis, he keeps one pea plant under gr

een light and the other pea plant under yellow light. What would likely be the result in a few days?

2 answers:

Komok [63]4 years ago

5 0

Answer:

Plants kept under yellow light would exhibit better growth and development.

Explanation:

The photosynthetic pigment of plant, chlorophyll, cannot absorb the green light and reflects it back. Hence, the pea plants kept under green light would not be able to carry out photosynthesis due to absence of light supporting the process. On the other hand, the plants kept under yellow light would exhibit better rate of photosynthesis and would exhibit better growth and development.

forsale [732]4 years ago

3 0

The one under the yellow light will be taller

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The graph below shows the time and position of a motorcycle as it travels

cluponka [151]

The answer is A. 1m/s

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3 years ago

A model airplane with a mass of 0.741kg is tethered by a wire so that it flies in a circle 30.9 m in radius. The airplane engine

Tju [1.3M]

Answer:

$_T}=24.57Nm$

ω = 0.0347 rad/s²

a ≅ 1.07 m/s²

Explanation:

Given that:

mass of the model airplane = 0.741 kg

radius of the wire = 30.9 m

Force = 0.795 N

The torque produced by the net thrust about the center of the circle can be calculated as:

$_T } = Fr$

where;

F represent the magnitude of the thrust

r represent the radius of the wire

Since we have our parameters in set, the next thing to do is to replace it into the above formula;

So;

$_T}=(0.795)*(30.9)$

$_T}=24.57Nm$

(b)

Find the angular acceleration of the airplane when it is in level flight rad/s²

$_T}=I \omega$

where;

I = moment of inertia

ω = angular acceleration

The moment of inertia (I) can also be illustrated as:

$I = mr^2$

I = ( 0.741) × (30.9)²

I = 0.741 × 954.81

I = 707.51 Kg.m²

$_T}=I \omega$

Making angular acceleration the subject of the formula; we have;

$\omega = \frac{_T}{I}$

ω = $\frac{24.57}{707.51}$

ω = 0.0347 rad/s²

(c)

Find the linear acceleration of the airplane tangent to its flight path.m/s²

the linear acceleration (a) can be given as:

a = ωr

a = 0.0347 × 30.9

a = 1.07223 m/s²

a ≅ 1.07 m/s²

5 0

3 years ago

Consider an ideal gas of 7 moles that is in contact with a thermal reservoir of temperature 475 K. The gas is enclosed in a cont

kozerog [31]

Answer:

(a). The initial pressure is $5.5\times10^{4}\ Pa$

(b). The final pressure is $1.8\times10^{4}\ Pa$

Explanation:

Given that,

Number of moles = 7

Temperature = 475 K

Initial volume = 0.50 m³

Expanded volume = 1.50 m³

We need to calculate the initial pressure

Using formula of pressure

$P_{i}=\dfrac{nRT_{i}}{V_{i}}$

Put the value into the formula

$P_{i}=\dfrac{7\times8.31\times475}{0.50}$

$P_{i}=55261.5\ Pa$

$P_{i}=5.5\times10^{4}\ Pa$

We need to calculate the final pressure

Using formula of pressure

$P_{f}V_{f}=nRT_{f}$

After expansion,

$\dfrac{P_{f}V_{f}}{P_{i}V_{i}}=\dfrac{nRT_{f}}{nRT_{i}}$

$P_{f}=\dfrac{T_{f}}{T_{i}}\times\dfrac{P_{i}V_{i}}{V_{f}}$

Put the value into the formula

For thermal process,

$T_{i}=T_{f}$

$P_{f}=\dfrac{5.5\times10^{4}\times0.50}{1.50}$

$P_{f}=18333.33\ Pa$

$P_{f}=1.8\times10^{4}\ Pa$

Hence, (a). The initial pressure is $5.5\times10^{4}\ Pa$

(b). The final pressure is $1.8\times10^{4}\ Pa$

3 0

4 years ago

Will a vector at 45 degrees to the horizontal be larger or smaller than its horizontal and vertical components? By how much?

never [62]

Larger. How big depends on the size of the vector. But think about pythagoras theorem to solve for the vector.

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sertanlavr [38]

Answer:

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3 years ago