Answer:
B
Step-by-step explanation:
In a function, every x-coordinate must be a different number.
If the same number appears more than once as an x-coordinate, it is not a function.
Answer: B
Answer:
If Sanjay wants to make 24 but the recipe makes 8, then do the recipe 3 times to get 24 (8 x 3 = 24)
135 x 3 = 405
1 x 3 = 3
2 x 3 = 6
130 x 3 = 390
1 x 3 = 3
2 x 3 = 6
So Sanjay would need the following to make 24 pancakes:
405g flour
3tsp baking powder
6tbsps sugar
390mL milk
3 eggs
6tbsps oil
The answer is: [C]: "no solution" .
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Given: 3y = 3/2 x + 6 ; Multiply each side by "2" ; to get rid of the fraction
2 * { 3y = 3/2 x + 6 } ; to get: 6y = 3x + 12
Given: 1/2 y –1/4 x = 3 ; Multiply EACH SIDE by "4" ; to get rid of the fraction ;
4 * { 1/2 y – 1/4 x = 3 } ; to get: 2y – x = 12 ;
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So we have:
6y = 3x + 12 ;
2y – x = 12 ;
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Multiply BOTH side of the "second equation" by "-1" ;
-1 * { 2y – x = 12 } ;
to get : x – 2y = -12 ;
Now, add "2y" to each side of the equation;
to isolate "x" on one side of the equation; & to solve for "x" ;
x – 2y + 2y = -12 + 2y ;
to get: x = 2y – 12 ;
Now, consider the "first equation" ;
6y = 3x + 12 ;
Divide EACH SIDE of this equation by "3" ;
6y / 3 = (3x + 12) / 3 ;
to get: 2y = x + 4 ;
Divide EACH SIDE of the equation by "2" ;
2y/ 2 = ( x + 4) /2 ;
to get: y = (x + 4) / 2 ;
Now plug in our calculated value for "x" ; which is:
" x = 2y – 12 " ; for the "x" values
y = [ (2y – 12)] + 4)] / 2 ;
y = (2y – 8 )/ 2
2y = 2y – 8 ??? ;;
The answer is: [C]: "no solution" .
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9514 1404 393
Answer:
72, 96
Step-by-step explanation:
6 and 8 are already multiples of 2. The prime factorization of these numbers is ...
6 = 2×3
8 = 2³
The least common multiple of these numbers must have factors of 2³ and 3. That number is ...
2³×3 = 24
Multiples of 24 less than 150 are ...
24, 48, 72, 96, 120, 144
Of these, the values in the range of interest are 72 and 96.
Ravi could choose 72 or 96.
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72 = 2×36 = 6×12 = 8×9
96 = 2×48 = 6×16 = 8×12
Answer:
17 rolls
Step-by-step explanation:
4 x 45 = 180
265-180 = 85
85 ÷ 5 = 17
hope this helps ;)
