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ivanzaharov [21]
3 years ago
12

Define critical point. Group of answer choices The temperature and pressure below which a supercritical fluid exists. The temper

ature and pressure above which a supercritical fluid exists. The temperature and pressure are equal. The temperature and pressure are not equal. The temperature and pressure where liquid, solid, and gas are equally stable and are in equilibrium.
Chemistry
1 answer:
attashe74 [19]3 years ago
8 0

Answer:

The temperature and pressure below which a supercritical fluid exists.

Explanation:

Critical point is a region on the phase diagram where fluid phases (liquids and gases) have the equal density.

This is caused by increased temperature and pressure of the fluid particles in a confided container. Supercritical fluids exist in a state above critical point.

I hope this explanation was clear.

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jasenka [17]

Answer:

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Explanation:

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3 0
3 years ago
Read 2 more answers
Given the two reactions H2S(aq)⇌HS−(aq)+H+(aq), K1 = 9.57×10−8, and HS−(aq)⇌S2−(aq)+H+(aq), K2 = 1.46×10−19, what is the equilib
Dvinal [7]

<u>Answer:</u> The value of K_c for the final reaction is 7.16\times 10^{25}

<u>Explanation:</u>

The given chemical equations follows:

<u>Equation 1:</u>  H_2S(aq.)\rightleftharpoons HS^-(aq.)+H^(aq.);K_1

<u>Equation 2:</u>  HS^-(aq.)\rightleftharpoons S^{2-}(aq.)+H^(aq.);K_2

The net equation follows:

S^{2-}(aq.)+2H^+(aq.)\rightleftharpoons H_2S(aq.);K_c

As, the net reaction is the result of the addition of reverse of first equation and the reverse of second equation. So, the equilibrium constant for the net reaction will be the multiplication of inverse of first equilibrium constant and the inverse of second equilibrium constant.

The value of equilibrium constant for net reaction is:

K_c=\frac{1}{K_1}\times \frac{1}{K_2}

We are given:

K_1=9.57\times 10^{-8}

K_2=1.46\times 10^{-19}

Putting values in above equation, we get:

K_c=\frac{1}{(9.57\times 10^{-8})}\times \frac{1}{(1.46\times 10^{-19})}=7.16\times 10^{25}

Hence, the value of K_c for the final reaction is 7.16\times 10^{25}

5 0
3 years ago
(reply w the answer or get reported) Ty if you answer this​
Dimas [21]

Answer:

D. 34.5g

Explanation:

Using the following formula to calculate the mass of 1.5moles of sodium (Na);

Mole = mass/molar mass

Molar mass of Na = 23g/mol

mass = mole × molar mass

Mass of Na = 1.5mol × 23g/mol

Mass of Na = 34.5g

3 0
2 years ago
Calculate the vapor pressure of a solution made by dissolving 109 grams of glucose (molar mass = 180.2 g/mol in 920.0 ml of wate
Fynjy0 [20]
Given data: <span>molar mass = 180.2 g/mol in 920.0 ml of water at 25 °c.
                   </span><span>the vapor pressure of pure water at 25 °c is 23.76 mm hg. 
</span>Asked: <span>the vapor pressure of a solution made by dissolving 109 grams of glucose
</span><span>
Solution:
moles glucose = 109 g/ 180.2 g/mol=0.605 
mass water = 920 mL x 1 g/mL = 920 g 
moles water = 920 g/ 18.02 g/mol=51.1 
mole fraction water = 51.1 / 51.1 + 0.605 =0.988 
vapor pressure solution = 0.988 x 23.76 = 23.47 mm Hg</span>
6 0
3 years ago
Which is one factor of rock types that affects the rate of weathering?
Luba_88 [7]

Answer:

B

Explanation:

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4 0
3 years ago
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