Answer:
Irrigation is the artificial process of applying controlled amounts of water to land to assist in production of crops. Irrigation helps to grow agricultural crops, maintain landscapes, and revegetate disturbed soils in dry areas and during periods of less than average rainfall.
When highly electronegative element like oxygen is directly attached to less electronegative element like hydrogen the electrons from less electronegative elements are attracted toward the highly electronegative element, making the less electronegative element deficient in electron density (partial positive) and a partial negative charge on more electronegative element is created. In such situation the intermolecular forces formed are dipole-dipole interactions or hydrogen bond interaction like in HF.
Answer:
0.4383 g
Explanation:
Molality is defined as the moles of the solute present in 1 kg of the solvent.
It is represented by 'm'.
Thus,
Given that:
Mass of solvent, water = 150 g = 0.15 kg ( 1 g = 0.001 g )
Molality = 0.050 m
So,
Molar mass of NaCl = 58.44 g/mol
Mass = Moles*Molar mass = 
= 0.4383 g
Answer:
6.39 × 10^23 kg (0.107 M⊕)
Explanation:
First, find the number of moles of glucose in 30.5 g.
You need the molar mass.
Molar mass of C6H12O6 = 6 * 12.01 g/mol + 12 * 1.01 g/mol + 6*16g/mol = 180.2 g/mol
number of moles = mass in grams / molar mass = 30.5 g / 180.2 g/mol = 0.169 mol
Second, use molecular formula
1 mol of C6H12O6 contains 6 moles of O.
Then, 0.169 moles of C6H12O6 contains 6 *0.169 = 1.014 moles of O.
Third, multiply by Avogagro's number:
1.014 moles * 6.022 * 10^23 atoms / mole = 6.106 * 10^ 23 atoms.
Answer: 6.106 * 10 ^23 atoms of oxygen.
