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aalyn [17]
3 years ago
9

Identify the examples of diffusion in the list below

Chemistry
2 answers:
rusak2 [61]3 years ago
6 0

Answer:1)Noxious smell of ammonia gas spread in the air  2)Cigarette smoke spreads into the air  3)Aroma of food spreads into the air

Explanation:

Sergeu [11.5K]3 years ago
3 0

Answer:

movement of particles of object from one place to another

e.g

spreading of perfume in air

spreading of ink in water

Explanation:

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Which separation method would be most successful in separating the components of a homogeneous mixture?
stiks02 [169]
I'm pretty sure the answer is B) Evaporation.
8 0
3 years ago
Read 2 more answers
A 10.00 g sample of a soluble barium salt is treated with an excess of sodium sulfate to precipitate 11.21 g BaSO4 (M- 233.4). W
aliina [53]

Answer:

The salt is barium chloride.

Explanation:

BaX_2++Na_2SO_4\rightarrow BaSO_4+2NaX

Moles of barium sulfate =\frac{11.21 g}{233.38 g/mol}=0.0480 mol

According to reaction, 1 mol of barium sulfate is produced from 1 mol of BaX_2.

Then 0.0480 moles will be produced from:

\frac{1}{1}\times 0.0480 mol=0.0480 mol of BaX_2.

Mass of BaX_2 used = 10.00 g

Moles of BaX_2 =\frac{10.00 g}{\text{Molar mass}}[/tex]

0.0480 mol=\frac{10.00}{\text{Molar mass}}

Molar mass of BaX_2 = 208.33 g/mol

The nearest answer to our answer is BaCl_2=208.2 g/mol.

The correct answer barium chloride with molar mass of 208.2 g/mol.

8 0
3 years ago
The elements of the group IA are termed as alkali metals, because their ___ are alkaline.
Vadim26 [7]

The answer is hydroxides.

The elements of the group IA are termed as alkali metals, because their hydroxides are alkaline.

7 0
2 years ago
PLEASE HELP & SHOW WORK
Olegator [25]

Answer:

1. 0.178 moles ; 2. 8x10²³ atoms ; 3. 7.22x10²³ molecules ; 4. 89.6 g ; 5. 1.34x10²² atoms ; 6. 1.67x10²⁵ molecules

Explanation:

1. Mass / Molar mass = Mol

5g / 28 g/m = 0.178 moles

2. 1 molecule of N₂ has 2 atoms, it is a dyatomic molecule.

4x10²³  x2 = 8x10²³ atoms

3. 1 mol of anything, has 6.02x10²³ particles

6.02x10²³ molecules . 1.2 mol = 7.22x10²³

4. 1 atom of C weighs 12 amu.

4.5x10²⁴ weigh ( 4.5x10²⁴ . 12) = 5.24x10²⁵ amu

1 amu = 1.66054x10⁻²⁴g

5.24x10²⁵ amu = (5.24x10²⁵ . 1.66054x10⁻²⁴) = 89.6 g

5. Molar mass NaCl = 58.45 g/m

1.3 g /  58.45 g/m = 0.0222 moles

1 mol has 6.02x10²³ atoms

0.0222 moles → ( 0.0222 . 6.02x10²³) = 1.34x10²²

6. Density of water is 1 g/mL, so 500 mL are contained in 500 g of water

Molar mass H₂O = 18 g/m

500 g / 18 g/m = 27.8 moles

6.02x10²³ molecules . 27.8 moles = 1.67x10²⁵

8 0
3 years ago
Describe the relationship between the radius of a cation and that of the atom from which it is formed. a. cations are much small
koban [17]
<h3><u>Answer;</u></h3>

Cations are much smaller than their corresponding parent

<h3><u>Explanation;</u></h3>
  • Parent atom has more electrons and thus the effective nuclear charge on each electron is less.
  • When a cation is formed electron(s) is/are lost. Thus the effective nuclear charge or simply put, the attraction of the nucleus towards the electrons increases. Therefore, due to greater pull, the nucleus pulls the shells towards it, there by reducing the size, which makes cations smaller than their corresponding parent.
3 0
3 years ago
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