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2 years ago

A container of oxygen with a volume of 60 L is heated from 300 K to 400 k, What is the new volume?

Chemistry

1 answer:

Lunna [17]2 years ago

7 0

Answer:

80L

Explanation:

V1/T1 = V2/T2

V2 = V1 T2/T1

T1 = 300K

V1 = 60L

T2 = 400K

V2 = ?

V2 = V1 T2/T1

V2 = (60L)(400K) / (300K)

V2 = 80L

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Consider the reaction: 2nh3(aq)+ocl−(aq)→n2h4(aq)+h2o(l)+cl−(aq) this three-step mechanism is proposed: nh3(aq)+ocl−(aq) ⇌k1k2 n

saw5 [17]

Yes, the mechanism sums to the reaction.

You add the equations, cancelling species that occur on opposite sides of the arrows.

Eq1: NH3(aq) + OCl^(-)(aq) → NH2Cl(aq) + OH^(-)(aq)

Eq2: NH2Cl(aq) + NH3(aq) → N2H5^(+)(aq) + Cl^(-)(aq)

Eq3: N2H5^(+)(aq) + OH^(-)(aq) → N2H4(aq) + H2O(l)

OA: 2NH3(aq) + OCl^(-)(aq) → N2H4(aq) + H2O(l) + Cl^(-)(aq)

6 0

3 years ago

A steel container filled with H₂ gas is at a pressure of 6.5 atm and a temperature of 22°C. If the container is placed near a fu

Yuki888 [10]

Answer: The new pressure is 7.1 atm

Explanation:

To calculate the final pressure of the system, we use the equation given by Gay-Lussac Law. This law states that pressure of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

$\frac{P_1}{T_1}=\frac{P_2}{T_2}$

where,

$P_1\text{ and }T_1$ are the initial pressure and temperature of the gas.

$P_2\text{ and }T_2$ are the final pressure and temperature of the gas.

We are given:

$P_1=6.5atm\\T_1=22^0C=(22+273)K=295K\\P_2=?\\T_2=50^0C=(50+273)K=323K$

Putting values in above equation, we get:

$\frac{6.5}{295}=\frac{P_2}{323}\\\\P_2=7.1$

Hence, the new pressure is 7.1 atm

8 0

3 years ago

EXTRA CREDIT

marin [14]

Answer:

$\huge\boxed{\sf 36\ H\ atoms}$

Explanation:

Molecular formula from Glucose:

C₆H₁₂O₆

3 moles of Glucose:

3C₆H₁₂O₆

In 1 mole of Glucose, there are 12 hydrogen atoms.

In 3 moles:

= 12 × 3

= 36 H atoms

$\rule[225]{225}{2}$

5 0

2 years ago

A Hydrocarbon C₄H₁₀ has a boiling point of 0, another hydrocarbon C₆H₁₄ has a boiling point of 69. What would you expect the boi

cupoosta [38]

If the trend is linear, that is boiling point increases by a constant amount for each additional saturated carbon, the boiling point of octane would be 69*2 because you are adding two saturated carbons. So the predicted boiling point is 138C, which is very close to the literature value

5 0

2 years ago

Read 2 more answers

Compare the solubility of silver chromate in each of the following aqueous solutions: Clear All 0.10 M AgCH3COO 0.10 M Na2CrO4 0

slavikrds [6]

Solution :

Comparing the solubility of silver chromate for the solutions :

$0.10 \ M \ AgCH_3COO$ ----- Less soluble than in pure water.

$0.10 \ M \ Na_2CrO_4$ ----- Less soluble than in pure water.

$0.10 \ M \ NH_4NO_3$ ----- Similar solubility as in the pure water

$0.10 \ M \ KCH_3COO$ ----- Similar solubility as in the pure water

The silver chromate dissociates to form :

$AgCrO_4 (s) \rightleftharpoons 2Ag^+ (aq) +CrO_4^{2-}(aq)$

When 0.1 M of $AgCH_3COO^-$ is added, the equilibrium shifts towards the reverse direction due to the common ion effect of $Ag^+$ , so the solubility of $Ag_2CrO_4$ decreases.

Both $AgCH_3COO$ and $KCH_3COO$ are neutral mediums, so they do not affect the solubility.

4 0

2 years ago