The answer is 267.93 g
Molar mass of CaBr2 is the sum of atomic masses of Ca and Br:
Mr(CaBr2) = Ar(Ca) + 2Ar(Br)
Ar(Ca) = 40 g/mol
Ar(Br) = 79.9 g/mol
Mr(CaBr2) = 40 + 2 * 79.9 = 199.8 g/mol
The percentage of Br in CaBr2 is:
2Ar(Br) / Mr(CaBr2) * 100 = 2 * 79.9 / 199.8 * 100 = 79.98%
Now make a proportion:
x g in 79.98%
335 g in 100%
x : 79.98% = 335 g : 100%
x = 79.98% * 335 g : 100%
x = 267.93 g
Answer:
YIkES One thing u can do i ask your teacher about it or say that u need help with it the cant make fun of u because u need help with your work.
Answer:
for instance :
water , H²O , and hydrogen peroxide . H²O² , are alike
in that their respective molecules are composed of hydrogen and oxygen atomd . hope its helpful . Good luck :)
That would be cause part of the sodium is pure and that means it still kind of has it properties when it was an element and that its i think.
