The 'net' force acting on the box is (9 - 3) = 6 newtons
in the direction that Carlos is pushing.
Force = (mass) x (acceleration)
6 = (3) x (acceleration)
Divide each side by 3 :
<em>2 m/s² = acceleration</em>
Answer:
So, the correct answer is <em><u>the strong nuclear force</u></em>. It actually pulls together nuetrons and protons that are in the nucleus. At very tiny distances only, like those inside the nucleus, so, this strong force succeded in dealing with the electromagnetic force, and it basically stops the electrical repulsion of protons from blowing apart the nucleus.
<u><em>Mark as brainlies please, I need a few more :D</em></u>
Maximum height
= (Usinα)^2/2g
(50*0.5)^2/20
25^2/20
625/20
=31.25metres
horizontal distance = Range= [U^2 * sin2α]/g
[50^2 * sin60]/10
2500 * 0.8660/10
2165/10=216.5metres
Answer:
1. The length is 8.35m
2. The period on the moon is 14.05 secs
Explanation:
1. Data obtained from the question. This includes the following:
Period (T) = 5.8 secs
Acceleration due to gravity (g) = 9.8 m/s2
Length (L) =...?
The length can be obtained by using the formula given below:
T = 2π√(L/g)
5.8 = 2π√(L/9.8)
Take the square of both side
(5.8)^2 = 4π^2 x L/ 9.8
Cross multiply
4π^2 x L = (5.8)^2 x 9.8
Divide both side by 4π^2
L = (5.8)^2 x 9.8 / 4π^2
L= 8.35 m
2. Data obtained from the question. This includes the following:
Acceleration due to gravity (g) = 1.67 m/s2
Length (L) = 8.35m (the length remains the same)
Period (T) =?
The period can be obtained as follow:
T = 2π√(L/g)
T = 2π√(8.35/1.67)
T = 14.05 secs
Therefore, the period on the moon is 14.05 secs
Answer:
Centripetal acceleration
Explanation:
- The centripetal acceleration is the motion inwards towards the center of a circular path.
- <em><u>Centripetal acceleration is given by; the square of the velocity, divided by the radius of the circular path.
</u></em>
ac = v²/r
Where; ac = acceleration, centripetal, m/s², v is the velocity, m/s and r is the radius, m
