What's the basic unit of the measurement of power

Physics

1 answer:

Jobisdone [24]3 years ago

7 0

Power is the RATE at which energy changes or flows.

The unit of energy is the Joule, so a unit of power is the Joule/second.

That unit has the special name "Watt".

Your question is not necessarily a question. It's also a statement, You could write

"Watt's the basic unit of the measurement of power".

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Measuring the volume of a ball that is 24cm across how can you set up an equation

BigorU [14]

The volume of every sphere is

   Volume = (4/3) (pi) (radius)³

When you say "across", I think you mean the diameter of the ball.
The radius is half of the diameter = 12 inches.

   Volume = (4/3) (pi) (12 inches)³

   = (4/3) (pi) (1,728 cubic inches)

   =    7,238.2 cubic inches . (rounded)

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8. Noticing how much food is on your lunch tray is a quantitative observation because

zhenek [66]

Answer:

you are making an observation that uses numbers.

Explanation:

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Air flows through an adiabatic turbine that is in steady operation. The air enters at 150 psia, 900oF, and 350 ft/s and leaves a

Nonamiya [84]

Answer:

$1486.5\frac{Btu}{s}$

Explanation:

The inlet specific volume of air is given by:

$v_1=\frac{RT_1}{P_1}\\\\v_1=\frac{(0.3704\frac{psia.ft^3}{lbm.R})(1360R)}{150psia}\\\\v_1=3.358\frac{ft^3}{lbm} \ \ \ \ \ \ \ \ \...i$

The mass flow rates is expressed as:

$\dot m=\frac{1}{v_1}A_1V_1\\\\\dot m=\frac{1}{3.358ft^3/psia}(0.1ft^2)(350ft/s)\\\\\dot m=10.42\frac{lbm}{s}$

The energy balance for the system can the be expresses in the rate form as:

$E_{in}-E_{out}=\bigtriangleup \dot E=0\\\\E_{in}=E_{out}\\\\\dot m(h_1+0.5V_1^2)=\dot W_{out}+\dot m(h_2+0.5V_2^2)+Q_{out}\\\\\dot W_{out}=\dot m(h_2-h_1+0.5(V_2^2-V_1^2))=-m({cp(T_2-t_1)+0.5(V_2^2-V_1^2)})\\\\\\\dot W_{out}=-(10.42lbm/s)[(0.25\frac{Btu}{lbm.\textdegree F})(300-900)\textdegree F+0.5((700ft/s)^2-(350ft/s)^2)(\frac{1\frac{Btu}{lbm}}{25037ft^2/s^2})]\\\\\\\\=1486.5\frac{Btu}{s}$