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Ronch [10]
2 years ago
6

You have managed to get a vacation on the Moon where the gravitational field strength is 1.6 N/kg. Gleefully, you kick a ball of

mass 1.25 kg with an initial velocity of < 12, 12, 0> m/s. There is a goal post you can use as an origin marker where you kicked the ball. What is the initial momentum of the ball?
Physics
1 answer:
sattari [20]2 years ago
4 0

The initial momentum of the ball is 15 Kgms-1.

<h3>What is momentum?</h3>

In Physics, the term momentum is the product of mass and velocity. Momentum is a vector quantity. This implies that momentum possess both magnitude and direction.

Hence, we often write; p = mv

Where:

p = momentum

m = mass

v = velocity

The initial momentum therefore is;

p = 1.25 kg × 12 m/s = 15 Kgms-1

Learn more about momentum: brainly.com/question/904448

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Answer:

F = f from Newton’s first law.

Explanation:

since the desk is moved in a straight line at a constant speed, newton first law tell us that the two forces must be equal.

Newton's First Law states that an object will remain at rest or in uniform motion in a straight line unless acted upon by an external force. since the table has been set in motion by the 400 N force, it will remain in motion unless it is been acted upon by an external force, and this means that the 400 N must be equal to the frictional force for it to have been in motion in the first instance.

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How fast, in rpm, would a 5.6 kg, 25-cm-diameter bowling ball have to spin to have an angular momentum of 0.26 kgm2/s
solong [7]

Answer:

71 rpm

Explanation:

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Angular momentum (L) = 0.26

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Moment of inertia (I) = 2mr² / 5

I = (2 * 5.6 * 0.125^2) / 5

= 0.175

= 0.175 / 5

= 0.035 kgm²

Angular speed (w) ;

w = L / I

w = 0.26 / 0.035

= 7.4285714

= 7.429 rad/s

w = (7.429 * 60/2π)

w = 445.74 / 2π rpm

w = 70.941724

Angular speed = 70.94 rpm

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Answer:

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