Part 1:
For this case we must see in the graph the axis of symmetry of the given parabola.
We have then that the axis of symmetry is the vertical line t = 2.
Answer:
The height of the javelin above the ground is symmetric about the line t = 2 seconds:
Part 2:
For this case, we must see the time t for which the javelin reaches a height of 20 feet for the first time.
We then have that when evaluating t = 1, the function is h (1) = 20. To do this, just look at the graph.
Then, we must observe the moment when it returns to be 20 feet above the ground.
For this, observing the graph we see that:
h (3) = 20 feet
Therefore, a height of 20 feet is again reached in 3 seconds.
Answer:
The javelin is 20 feet above the ground for the first time at t = 1 second and again at t = 3 seconds
Answer:
-31/6
Step-by-step explanation:
77+2(3x-5)=8-3(2x+1)
77+6x-10=8-6x-3
77-10+6x=8-3-6x
67+6x=5-6x
67+6x-(-6x)=5
67+6x+6x=5
67+12x=5
12x=5-67
12x=-62
x=-62/12
simplify
x=-31/6
Answer:
y=-5,x=2
Step-by-step explanation:
3x+3y=-9________________eqn 1
3x-3y=21________________eqn 2
using elimination method
3x+3y=-9
-
3x-3y=21
subtract equation 2 from equation 1
0+6y=-30
6y=-30
y=-30/6
y=-5
substitute the value of y in equation 1
3x+3y=-9
3x+3(-5)=-9
3x-15=-9
3x=-9+15
3x=6
x=6/3
x=2
Answer:
?????????????????????????????????????????????????????????????????????/
Step-by-step explanation:
0.2:1
I divided 3 by 15 and got 0.2 and then divided 15 by 15 to get one
