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gulaghasi [49]
3 years ago
14

1/10 + 20/100= 2/3+ 1/4 = ANSWERS ASAP!! RIGHT ANSWERS GET AUTOMATIC BRAINLYEST

Mathematics
2 answers:
Bess [88]3 years ago
7 0

Answer:

\frac{1}{10}  +  \frac{20}{100}  =  \frac{10}{100}  +  \frac{20}{100}  =  \frac{30}{100}

\frac{2}{3}  +  \frac{1}{4}  =  \frac{8}{12}  +  \frac{3}{12}  =  \frac{11}{12}

Lyrx [107]3 years ago
6 0
3/10 and 11/12 jejejakanwjwiaowkwjjwjwja
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. How many solutions does this system of equations have?<br> y = 4x - 2.<br> y = 4x +5 *
defon

Answer:

No solutions

Step-by-step explanation:

Solve for the first variable in one of the equations, then substitute the result into the other equation.

3 0
3 years ago
The equation of a straight line is y+10=5x
MariettaO [177]

Answer:

y=5x-10

Step-by-step explanation:

y+10=5x

y=5x-10

4 0
4 years ago
A pair of shoes at Nordstrom‘s costs $120. The shoes are on sale for 15% off. You have a coupon that allows you to take an addit
iVinArrow [24]
$120 with 25% taken off of it would be $90 !
3 0
3 years ago
Three times x less than y is five times y plus two times x in a verbal sentence please help
tankabanditka [31]
SOLUTION:

As an equation it is:

y - 3x = 5y + 2x

If you are asking for it as a sentence ( I will do it as a written sentence as I unfortunately can't show you the sentence verbally as you had asked ), then it is as you had written in your question so:

Three times x less than y is five times y plus two times x

Or you could write is as:

y subtracted by three times x is equivalent to the sum of five times y and two times x.

Essentially, even with the small alterations that you can make to the phrasing and sentence structure, the concepts are the same so you can use one of the above answers or alter it as you please.

Hope this helps! :)
6 0
3 years ago
If you had 1052 toothpicks and were asked to group them in powers of 6, how many groups of each power of 6 would you have? Put t
sukhopar [10]

1052 toothpicks can be grouped into 4 groups of third power of 6 (6^{3}), 5 groups of second power of 6 (6^{2}), 1 group of first power of 6 (6^{1}) and 2 groups of zeroth power of 6 (6^{0}).

The number 1052, written as a base 6 number is 4512

Given: 1052 toothpicks

To do: The objective is to group the toothpicks in powers of 6 and to write the number 1052 as a base 6 number

First we note that, 6^{0}=1,6^{1}=6,6^{2}=36,6^{3}=216,6^{4}=1296

This implies that 6^{4} exceeds 1052 and thus the highest power of 6 that the toothpicks can be grouped into is 3.

Now, 6^{3}=216 and 216\times 5=1080, 216\times 4=864. This implies that 216\times 5 exceeds 1052 and thus there can be at most 4 groups of 6^{3}.

Then,

1052-4\times6^{3}

1052-4\times216

1052-864

188

So, after grouping the toothpicks into 4 groups of third power of 6, there are 188 toothpicks remaining.

Now, 6^{2}=36 and 36\times 5=180, 36\times 6=216. This implies that 36\times 6 exceeds 188 and thus there can be at most 5 groups of 6^{2}.

Then,

188-5\times6^{2}

188-5\times36

188-180

8

So, after grouping the remaining toothpicks into 5 groups of second power of 6, there are 8 toothpicks remaining.

Now, 6^{1}=6 and 6\times 1=6, 6\times 2=12. This implies that 6\times 2 exceeds 8 and thus there can be at most 1 group of 6^{1}.

Then,

8-1\times6^{1}

8-1\times6

8-6

2

So, after grouping the remaining toothpicks into 1 group of first power of 6, there are 2 toothpicks remaining.

Now, 6^{0}=1 and 1\times 2=2. This implies that the remaining toothpicks can be exactly grouped into 2 groups of zeroth power of 6.

This concludes the grouping.

Thus, it was obtained that 1052 toothpicks can be grouped into 4 groups of third power of 6 (6^{3}), 5 groups of second power of 6 (6^{2}), 1 group of first power of 6 (6^{1}) and 2 groups of zeroth power of 6 (6^{0}).

Then,

1052=4\times6^{3}+5\times6^{2}+1\times6^{1}+2\times6^{0}

So, the number 1052, written as a base 6 number is 4512.

Learn more about change of base of numbers here:

brainly.com/question/14291917

6 0
3 years ago
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