All categories

3 years ago

How to multiply this problem

Mathematics

1 answer:

forsale [732]3 years ago

7 0

To multiply 13.26 times 23, we first have to set it up vertically.
13.26
x 23
--------
3978
2652
----------
30498
Adding in the decimal, we get 304.98, because the total amount of decimal numbers in the equation, is 2. Therefore, the answer will have 2 decimal numbers. I hope this helps! :D But, if you don't understand how to multiply, tell me. I'm pretty sure that you do, but you know, just in case!

You might be interested in

Please help me answer this question

stealth61 [152]

The value of dy/dx for the functions are

(i) $\frac{dy}{dx} = 4x^{2}sin2x.cos2x+ 2x. sin^{2}2x$

(ii) $\frac{dy}{dx} =\frac{- y(1+3x^{2})}{2x(1+x^{2}) }$

<h3>Differentiation</h3>

From the question, we are to determine dy/dx for the given functions

(i) $x^{2} sin^{2}2x$

Let $u = x^{2}$

and

$v = sin^{2} 2x$

Also,

Let $w= sin2x$

∴ $v = w^{2}$

First, we will determine $\frac{dv}{dx}$

Using the Chain rule
$\frac{dv}{dx} = \frac{dv}{dw}.\frac{dw}{dx}$

$v = w^{2}$

∴ $\frac{dv}{dw} =2w$

Also,

$w= sin2x$

∴ $\frac{dw}{dx} =2cos2x$

Thus,

$\frac{dv}{dx} = 2w \times 2cos2x$

$\frac{dv}{dx} = 2sin2x \times 2cos2x$

$\frac{dv}{dx} = 4sin2x . cos2x$

Now, using the product rule

$\frac{dy}{dx} = u\frac{dv}{dx} + v\frac{du}{dx}$

From above

$u = x^{2}$

∴ $\frac{du}{dx}=2x$

Now,

$\frac{dy}{dx} = x^{2} (4sin2x.cos2x)+ sin^{2}2x (2x)$

$\frac{dy}{dx} = 4x^{2}sin2x.cos2x+ 2x. sin^{2}2x$

(ii) $xy^{2}+y^{2}x^{3} +2=0$

Then,

$x.2y\frac{dy}{dx}+ y^{2}(1)+y^{2}.3x^{2} + x^{3}.2y\frac{dy}{dx} +0=0$

$2xy\frac{dy}{dx}+ y^{2}+3x^{2}y^{2} + 2x^{3}y\frac{dy}{dx} =0$

$2xy\frac{dy}{dx}+2x^{3}y\frac{dy}{dx} =- y^{2}-3x^{2}y^{2}$

$\frac{dy}{dx} (2xy+2x^{3}y)=- y^{2}(1+3x^{2})$

$\frac{dy}{dx} =\frac{- y^{2}(1+3x^{2})}{2xy+2x^{3}y}$

$\frac{dy}{dx} =\frac{- y^{2}(1+3x^{2})}{2xy(1+x^{2}) }$

$\frac{dy}{dx} =\frac{- y(1+3x^{2})}{2x(1+x^{2}) }$

Hence, the value of dy/dx for the functions are

(i) $\frac{dy}{dx} = 4x^{2}sin2x.cos2x+ 2x. sin^{2}2x$

(ii) $\frac{dy}{dx} =\frac{- y(1+3x^{2})}{2x(1+x^{2}) }$

Learn more on Differentiation here: brainly.com/question/24024883

#SPJ1

8 0

2 years ago

Please help<br> With this math

pshichka [43]

The answer is certainly c because i did that and got it right

7 0

3 years ago

(a) Write down the gradient of the line with equation y = 7 - 4x The line L passes through the points with coordinates (- 3, 1)

lesya [120]

Note: Let us consider, we need to find the gradient of line L.

Given:

The given equation of a line is:

$y=7-4x$

The line L passes through the points with coordinates (- 3, 1) and (2, - 2).

To find:

The gradient of the given line and the gradient of line L.

Solution:

Slope intercept form of a line is:

$y=mx+b$ ...(i)

We have,

$y=7-4x$ ...(ii)

On comparing (i) and (ii), we get

$m=-4$

Therefore, the gradient of the given line is -4.

The line L passes through the points with coordinates (- 3, 1) and (2, - 2). So, the gradient of line L is:

$m=\dfrac{y_2-y_1}{x_2-x_1}$

$m=\dfrac{-2-1}{2-(-3)}$

$m=\dfrac{-3}{2+3}$

$m=\dfrac{-3}{5}$

Therefore, the gradient of the line L is $\dfrac{-3}{5}$ .

6 0

3 years ago

Marvin Company has a beginning inventory of 12 sets of paints at a cost of $1.60 each. During the year, the store purchased 4 se

Firlakuza [10]

Answer:

Explanation:

Trust me bro

4 0

3 years ago

The length of human pregnancies from conception to birth is normally distributed with mean 266 days and standard deviation 16 da

Sidana [21]

Answer:

68 %

Step-by-step explanation:

(a) Using the 68-95-99.7% rule, between what two lengths do the most typical 68% of all pregnancies fall?

95%? 99.7%?

The middle 68% of all pregnancies last between 266-16 and 266+16 days, 250 to 282. The middle 95% of all

pregnancies last between 266-2*16 and 266+2*16 days, 234 to 298 (for future reference, note that this “rule” is

rounded somewhat compared to the charts). The middle 99.7% of all pregnancies last between 266-3*16 and

266+3*16 days, 218 to 314.

3 0

4 years ago