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mel-nik [20]
3 years ago
11

If x = -12, y = -3; find xy?​

Mathematics
2 answers:
Aleksandr-060686 [28]3 years ago
4 0

Answer:

36

Step-by-step explanation:

To find xy, multiply x and y

(-12)(-3) = 36

xy = 36

wolverine [178]3 years ago
3 0

<u>Given </u><u>that</u><u> </u><u>:</u><u>-</u><u> </u>

  • x = -12
  • y = -3

<u>To</u><u> </u><u>Find</u><u> </u><u>:</u><u>-</u><u> </u>

  • Value of xy

<u>S</u><u>o</u><u>l</u><u>u</u><u>t</u><u>i</u><u>o</u><u>n</u><u> </u><u>:</u><u>-</u><u> </u>

<u>☆</u><u> </u>When a negative digit is multiplied with negative digit then the result comes as positive digit .

→ x × y = (-12)(-3)

→ x.y = 36

So the answer is 36.

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Answer:

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Step-by-step explanation:

Let

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Pr = 0.5^N

For 2 boxes, it is:

Pr = 2 * 0.5^N

From the question, we have:

\frac{80}{10000} \to Favorable outcome

To solve for N, we have:

2 * 0.5^N = \frac{80}{10000}

2 * 0.5^N = 0.008

Divide both sides by 2

0.5^N = 0.004

Take log of both sides

\log(0.5^N) = \log(0.004)

Apply law of logarithm

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Make N the subject

N = \frac{\log(0.004)}{\log(0.5)}

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N = 8

Solving (b): Balls in one of the two boxes.

Here, we assume that each ball will have almost the same number of balls at a given instance;

Hence, we have:

Balls \approx \frac{N}{2}

Balls \approx \frac{8}{2}

Balls \approx 4

<em>4 balls in each box</em>

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Step-by-step explanation:

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Answer:

x=106 degrees

Step-by-step explanation:

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So you want to add 164 and 90 together and subtract the sum by 360

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