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3 years ago

Acid rain can be destructive to both the natural environment and human-made structures. The equation below shows a

Chemistry

1 answer:

guapka [62]3 years ago

3 0

Answer:

Explanation:

What the equation is tell you is that for every 3 mols of NO2 you get 2 mol of HNO3

3 mol NO2 / 2 mol HNO2 ===> 300.00 mol NO2 / x Cross multiply

3x = 2 * 300

3x = 600 Divide by 3

3x/3 = 600/3 Do the division

x = 200.00

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You have 25.0mL HCl of unknown concentration. It takes 12.5 mL of 0.2 M NaOH to neutralize the acid. Determine the concentration

Ugo [173]

Answer:

1) The concentration of HCl = 0.1 M.

2) The table that can be used to organize the information correctly is C.

Explanation:

1) The concentration of HCl:

We know that the no. of millimoles of the acid is equal to the no. of millimoles of the base at the neutralization point.

which means that: (MV)HCl = (MV)NaOH,

M of HCl = ??? M, V of HCl = 25.0 mL.

M of NaOH = 0.2 M, V of NaOH = 12.5 mL.

∴ M of HCl = (MV)NaOH/V of HCl = (0.2 M)(12.5 mL)/(25.0 mL) = 0.1 M.

2) The table that can be used to organize the information correctly is C

Table A and B are the same and reported volume of HCl and NaOH is wrong.

Table C is right, contain the correct volumes and concentration of NaOH and missed the concentration of HCl which is 0.1 M.

Table D reported the volume and the concentration of HCl wrongly and also the concentration of NaOH. The data reported of HCl and NaOH is reversed.

6 0

3 years ago

Compared to the ideal bond angle, the actual/real bond angle in a molecule of water will be:______.

inna [77]

Answer: d. smaller.

Explanation:

Hybridization :

$N=\frac{1}{2}[V+N+A-C]$

N = number of electrons

where, V = number of valence electrons present in central atom i.e. oxygen = 6

N = number of monovalent atoms bonded to central atom=32

C = charge of cation = 0

A = charge of anion = 0

The number of electrons is 4 that means the hybridization will be $sp^3$ and the electronic geometry of the molecule will be tetrahedral. The bond angle for tetrahedral geometry is $109.5^0$

But as there are two atoms around the central oxygen, the third and fourth position will be occupied by lone pair of electrons. The repulsion between lone and bond pair of electrons is more and hence the molecular geometry will be bent and the bond angle will be smaller than expected and is $104.5^0$

8 0

3 years ago

By definition, a(n) _______acid is any species that can donate a proton. Ammonia has a proton bonded to nitrogen, so ammonia can

pochemuha

Answer:

A Brønsted-Lowry acid.

A Brønsted-Lowry base.

Ammonia is an acceptor of proton.

Explanation:

A Brønsted-Lowry acid is any atom that can donate a proton (H +) to another atom or molecule whereas Brønsted-Lowry base is any species that can accept a proton from another atom or molecule or in other words, a Brønsted-Lowry acid is a proton donor, while on the other hand, a Brønsted-Lowry base is a proton acceptor. The ammonia molecule accepts the hydrogen ion is considered as the Brønsted-Lowry base.

5 0

3 years ago

If 550 mL of a 3.50 M KCl solution are set aside and alowed to evaporate unti the

andrezito [222]

1) list givens and convert if necessary

C₁ = 3.50 mol/L

V₁ = 0.550 L

C₂ = ?

V₂ = 0.275 L

2) rearrange formula

$C_{1}V_{1}=C_{2}V_{2}\\\\C_{2}=\frac{C_{1}V_{1}}{V_{2}}$

3) solve

$C_{2}=\frac{(3.50\ mol/L)(0.550\ L)}{(0.275\ L)}$

C₂ = 7.00 mol/L

5 0

3 years ago

Gaseous compound Q contains only xenon and oxygen. When a 0.100 g sample of Q is placed in a 50.0-mL steel vessel at 0 C, the pr

Paladinen [302]

The question is incomplete, here is the complete question:

Gaseous compound Q contains only xenon and oxygen. When a 0.100 g sample of Q is placed in a 50.0-mL steel vessel at 0°C, the pressure is 0.230 atm. What is the likely formula of the compound?

A. XeO

B. $XeO_4$