Assuming M is midpoint of RS
the midpoint formula is
x term of the midpoint is average of the x value of the 2 points
y term of the midpoint is average of the y value of the 2 points
if R is (x,y)
S is (6,1)
x value of midpoint is 4
x value of S is 6
x value os R is x
so
average of x and 6 is 4,
(x+6)/2=4,
x+6=8,
x=2
y value of midoint is 2
y value of S is 1
y value of R is y
average of 1 and y is 2
(y+1)/2=2
y+1=4
y=3
the midpoint is (2,3)
Well this is a hard question to answer, but this is how i would put it.
You would take a number (lets use 15) and the second number (lets use 5) would determine how many times it would go into 15. In other words, 5 time x would equal 15 (5x=15). 5, being a factor of 15, would evenly fit into 15 three times.
Step-by-step explanation:
55 > 4u + 15
40 > 4u
10 > u
so, this is true for all u < 10
Answer:
70.15 ft²
Step-by-step explanation:
The figure consists of two adjacent equilateral triangles (all angles are 60 degrees and all outer edges are 9 ft).
If we focus on one of these equilateral triangles, we can get the final area by multiplying the area of that one triangle by 2.
The formula for the area of a triangle is (1/2)(base)(height). Remembering to multiply this by 2, we get
area of figure = (base)(height)
√3
= (9 ft)(9 ft)(--------) = (81 ft²)(1.732) = 70.15 ft²
2
Answer: They can order from 0 to 449 bars, but no more.
Step-by-step explanation:
Given: The school band is ordering health bars to sell for a fundraiser. The company that sells the bars charges $0.40 per bar plus $20.00 for shipping regardless of the size of the order. The band must spend less than $200.00 on bars for the fundraiser.
The inequality below relates x, the number of bars that could be ordered, with the shipping costs and their spending requirements.

To solve for x, subtract 20 on both sides, we get

Divide 0.40 on both sides, we get
......... → the number of bars that could be ordered, with the shipping costs and their spending requirements must less than 450.
Thus, they can order from 0 to 449 bars, but no more.