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3 years ago

IN A RECTANGLE PQRS , PR = 25 AND THE AREA IS 168. WHAT IS THE MEASURE OF PQ?

Mathematics

1 answer:

Novay_Z [31]3 years ago

3 0

Answer:

the answer is 143

Step-by-step explanation:

just do 168 - 25 equals 143 , I'm sorry if I got this wrong I'm going based off what my 10th grade math teacher are taught me

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VladimirAG [237]

The top answer is correct.

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3 years ago

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nikdorinn [45]

Create a ratio and cross multiply

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4 years ago

Tickets to the school play cost $4.00 for adults and $2.00 for students. If 85 people attend the show, and the receipts totaled

qwelly [4]

Answer:I think it is 226

Step-by-step explanation:

85/2= 42.5 then 268 - 42.5= 225.5 then round it and you get 226

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4 years ago

An artist wishes to make a painting in the shape of a golden rectangle, based on the theory that this shape is the most pleasing

Arisa [49]

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3 years ago

Which are the roots of the quadratic function f(b) = 62 – 75? Select two options.

elena55 [62]

Answer:

$b = 5 \sqrt{3} \ or\ b = -5 \sqrt{3}$

Step-by-step explanation:

Given

$f(b) = b^2 - 75$

Required

Determine the roots

To get the root of the function, then f(b) must be 0;

i.e. f(b) = 0

So, the expression becomes

$0 = b^2 - 75$

Add 75 to both sides

$75 + 0 = b^2 - 75 + 75$

$75 = b^2$

Take square roots of both sides

$\sqrt{75} = \sqrt{b^2}$

$\sqrt{75} = b$

Reorder

$b = \sqrt{75}$

Expand 75 as a product of 25 and 3

$b = \sqrt{25*3}$

Split the expression

$b = \sqrt{25} *\sqrt{3}$

$b = \±5 *\sqrt{3}$

$b = \±5 \sqrt{3}$

$b = 5 \sqrt{3} \ or\ b = -5 \sqrt{3}$

The options are not clear enough; however the roots of the equation are $b = 5 \sqrt{3} \ or\ b = -5 \sqrt{3}$

4 0

3 years ago