Answer:
in degree 11.54
in radians 0.20
Step-by-step explanation:
soh= o/h
sin(y)=4/20
y=sin^-1(4/20)
I think the answer is "the denominator"
Answer:
a) 0.06 = 6% probability that a person has both type O blood and the Rh- factor.
b) 0.94 = 94% probability that a person does NOT have both type O blood and the Rh- factor.
Step-by-step explanation:
I am going to solve this question treating these events as Venn probabilities.
I am going to say that:
Event A: Person has type A blood.
Event B: Person has Rh- factor.
43% of people have type O blood
This means that 
15% of people have Rh- factor
This means that 
52% of people have type O or Rh- factor.
This means that 
a. Find the probability that a person has both type O blood and the Rh- factor.
This is

With what we have

0.06 = 6% probability that a person has both type O blood and the Rh- factor.
b. Find the probability that a person does NOT have both type O blood and the Rh- factor.
1 - 0.06 = 0.94
0.94 = 94% probability that a person does NOT have both type O blood and the Rh- factor.
Answer:
AL=aa2+4h2
IS the formula for square pyramid.
Answer:
he multiplied by 0.8 not .08
Step-by-step explanation:
when doing 8% you go back 2 places so 0.08
34×0.08= 2.72
34+2.72= 36.72