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Gala2k [10]
4 years ago
12

A water agency stated that waterlines cannot have water flowing faster than 8 ft/s. What is the minimum standard pipe diameter t

hat can transport 1750 gal/min without exceeding this limit?
Engineering
1 answer:
Lina20 [59]4 years ago
6 0

Answer:

The minimum standard diameter is 0.787 ft

Explanation:

Speed = 8 ft/s

Volumetric flow rate = 1750 gal/min = 1750 gal/min × 1 ft^3/7.481 gal × 1 min/60 s = 3.899 ft^3/s

Area of pipe (A) = volumetric flow rate ÷ speed = 3.899 ft^3/s ÷ 8 ft/s = 0.487 ft^2

Diameter of pipe = sqrt(4A/π) = sqrt(4×0.487/3.142) = sqrt(0.61999) = 0.787 ft

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A reversible power cycle R and an irreversible power cycle I operate between the same hot and cold thermal reservoirs. Cycle I h
anygoal [31]

Answer: Attached below is the missing diagram

answer :

A)   1) Wr > WI,     2) Qc' > Qc

B)   1) QH' > QH,   2) Qc' > Qc

Explanation:

  л = w / QH = 1 - Qc / QH  and  QH = w + Qc

<u>A) each cycle receives same amount of energy by heat transfer</u>

<u>(</u> Given that ; Л1 = 1/3 ЛR )

<em>1) develops greater bet work </em>

WR develops greater work ( i.e. Wr > WI )

<em>2) discharges greater energy by heat transfer</em>

 Qc' > Qc

solution attached below

<u>B) If Each cycle develops the same net work </u>

<em>1) Receives greater net energy by heat transfer from hot reservoir</em>

QH' > QH   ( solution is attached below )

<em>2) discharges greater energy  by heat transfer to the cold reservoir</em>

Qc' > Qc

solution attached below

4 0
3 years ago
A model shows a city located between a warm ocean and next to coastal mountains. Which statement best describes average weather
DanielleElmas [232]

Answer:

The city will experience high levels of rainfall.

8 0
3 years ago
Read 2 more answers
Name three types of large motor vehicles with which you might share the roadway. Explain how you can reduce risk when interactin
alexdok [17]

Answer:

rucks, buses, RVs, trolleys

Explanation:

What are some different types of vehicles that we share the road with?

Driving is a complex task, and for safe driving you need to know not just the rules of sharing the road with other cars, but with variety of other types of vehicles: trucks, buses, RVs, trolleys, motorcycles, bicycles and of course pedestrians.

8 0
2 years ago
An inventor claims to have developed a food freezer that at steady state requires a power input of 0.25 kW to extract energy by
Serga [27]

Answer:

investor claim is acceptable

Explanation:

given data

Win = 0.25 kW

Qc = 3000 J/s = 3kW

Th = 293 K

Tc = 270 K

solution

we get here coefficient of performance of cycle is

coefficient of performance = \frac{Qc}{Win}    ..................1

put here value and we get

coefficient of performance = \frac{3}{0.25}  

coefficient of performance = 1.2

and

coefficient of performance of ideal refrigeration is

coefficient of performance = \frac{Tc}{Th-Tc}    ..................2

coefficient of performance = \frac{270}{293-270}  

coefficient of performance = 11.74

and

we can see here that coefficient of performance of ideal refrigeration  is is more than real cycle coefficient of performance

so investor claim is acceptable

6 0
3 years ago
The output voltage of a power supply is normally distributed with mean 12 V and standard deviation 0.11 V. If the upper and lowe
podryga [215]

Answer:

82.62%

Explanation:

The z score is a score used in statistics to determine by how many standard deviations the raw score is above or below the mean. The z score is given by:

z=\frac{x-\mu}{\sigma} \\\\where\ x=raw\ score,\mu=mean\ and\ \sigma=standard\ deviation.\\\\Given \ that\ \mu=12V, \sigma=0.11V.\\\\For\ x11.85V:\\\\z=\frac{11.85-12}{0.11} =-1.36\\\\

From the normal distribution table, P(11.85 < x < 12.15) = P(-1.36 < z < 1.36) = P(z < 1.36) - P(z < -1.36) = 0.9131-0.0869 = 0.8262 = 82.62%

4 0
3 years ago
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