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3 years ago

List a minimum of four reasons why you might be rejected for a job offer.

Engineering

1 answer:

Digiron [165]3 years ago

3 0

- you appeared to the interview with a messy appearance

- you did not show up to the interview on time

- you might've not talked with proper grammar

- not very good communication with the person interviewing you

( i hope this helps :'D and remember that u r loved and very much appreciated, make sure to drink water and eat something !! <3 )

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A ten-station transfer machine has an ideal cycle time of 30 sec. The frequency of line stops is 0.075 stops per cycle. When a l

goldfiish [28.3K]

Answer:

62.5%

Explanation:

We are given that

A ten-station transfer machine has ideal cycle time=30 sec= $\frac{30}{60}=0.5 min$

Frequency of line=0.075 stops per cycle

Average time=4 min

We have to determine the line efficiency

$T_p=0.5+0.075(4)=0.5+0.3=0.8$

Line efficiency= $\frac{0.5}{0.8}\times 100=$ 62.5%

Hence, the line efficiency=62.5%

8 0

4 years ago

A(n) BLANK authenticates various specimens in a collection for a museum.

mezya [45]

Answer:

Curators

Explanation:

4 0

3 years ago

Which of the following is true of the difference between film acting and stage acting?

vladimir1956 [14]

There are several differences between film acting and stage acting. One difference is a stage actor is usually in front of a live audience. A film actor is not in front of a live audience.

Further Explanation:

There are numerous other ways that film and stage acting is different. In addition to the audiences, there is the extreme action shots that a film actor can accomplish where a stage actor cannot.

Other notable differences are;

Stage actors complete their roles continuous without breaks, except for intermission.
Film actors will film a scene many times to get it right and can take several breaks throughout the production.
Film actors generally make more money than a stage actor.
For a film actor they do not have a direct link with audiences and immediate feedback.
The types of acting such as theater drama versus action packed films.

Learn more about film actors at brainly.com/question/3511000

#LearnwithBrainly

4 0

3 years ago

For a bolted assembly with eight bolts, the stiffness of each bolt is kb = 1.0 MN/mm and the stiffness of the members is km = 2.

rjkz [21]

Answer:

a) 0.978

b) 0.9191

c) 1.056

d) 0.849

Explanation:

Given data :

Stiffness of each bolt = 1.0 MN/mm

Stiffness of the members = 2.6 MN/mm per bolt

Bolts are preloaded to 75% of proof strength

The bolts are M6 × 1 class 5.8 with rolled threads

Pmax =60 kN, Pmin = 20kN

a) Determine the yielding factor of safety

$n_{p} = \frac{S_{p}A_{t} }{CP_{max}+ F_{i} }$ ------ ( 1 )

Sp = 380 MPa, At = 20.1 mm^2, C = 0.277, Pmax = 7500 N, Fi = 5728.5 N

Input the given values into the equation above

equation 1 becomes ( np ) = $\frac{380*20.1}{0.277*7500*5728.5}$ = 0.978

note : values above are derived values whose solution are not basically part of the required solution hence they are not included

b) Determine the overload factor of safety

$n_{L} = \frac{S_{p}A_{t}-F_{i} }{C(P_{max} )}$ ------- ( 2 )

Sp = 380 MPa, At = 20.1 mm^2, C = 0.277, Pmax = 7500 N, Fi = 5728.5 N

input values into equation 2 above

hence : $n_{L}$ = 0.9191 $n_{L} = 0.9191$

C) Determine the factor of safety based on joint separation

$n_{0} = \frac{F_{i} }{P_{max}(1 - C ) }$

Fi = 5728.5 N, Pmax = 7500 N, C = 0.277,

input values into equation above

Hence $n_{0}$ = 1.056

D) Determine the fatigue factor of safety using the Goodman criterion.

nf = 0.849

attached below is the detailed solution .

4 0

3 years ago

Applying the Entropy Balance: Closed Systems Five kg of carbon dioxide (CO2) gas undergoes a process in a well-insulated piston–

Mrrafil [7]

Answer:

a) the amount of energy produced in kJ/K is 0.73145 kJ/K

b) the amount of energy produced in kJ/K is 0.68975 kJ/K

The value for entropy production obtained using constant specific heats is approximately 6% higher than the value obtained when accounting explicitly for the variation in specific heats.

Explanation:

Draw the T-s diagram.

$C_p$ = 0.939 kJ/kg.K , m = 5 kg , T₂ = 520 K , T₁ = 280

R = [8.314 kJ / 44.01 kg.K] , P₂ = 20 bar , P₁ = 2 bar

Δs = $m[c_p ln(\frac{T_2}{T_1}) - Rln(\frac{P_2}{P_1})]$

Substitute all parameters in the equation

Δs = $5[(0.939) ln(\frac{520}{280}) - (\frac{8.314}{44.01})ln(\frac{20}{2})]$

Δs = 5 kg × 0.14629 kJ/kg.K

= 0.73145 kJ/K

Δs = $m[\frac{s^0(T_2) - s^0(T_1)}{M} - Rln(\frac{P_2}{P_1})]$

Where T₁ = 280 K , s°(T₁) = 211.376 kJ/kmol.K

T₂ = 520 K , s°(T₂) = 236.575 kJ/kmol.K

R = [8.314 kJ / 44.01 kg.K] , M = 44.01 kg.K , P₂ = 20 bar , P₁ = 2 bar

Δs = $5[\frac{236.575 - 211.376}{44.01} - (\frac{8.314}{44.01})ln(\frac{20}{2})]$

= 5 kg (0.13795 kJ/kg.K)

= 0.68975 kJ/K

The value for entropy production obtained using constant specific heats is approximately 6% higher than the value obtained when accounting explicitly for the variation in specific heats.

7 0

4 years ago