Answer:
Energy produce in one year =20.49 x 10¹⁶ J/year
Explanation:
Given that
Plant produce 6.50 × 10⁸ J/s of energy.
It produce 6.50 × 10⁸ J in 1 s.
We know that
1 year = 365 days
1 days = 24 hr
1 hr = 3600 s
1 year = 365 x 24 x 3600 s
1 year = 31536000 s
So energy produce in 1 year = 31536000 x 6.50 × 10⁸ J/year
Energy produce in one year = 204984 x 10¹² J/year
Energy produce in one year =20.49 x 10¹⁶ J/year
Where are the statements then bbs lol
“Thinking about pleasant things to pass the time” would not promote safety in the shop because it would be taking the focus away from important tasks, which in turn decreases safety.
Answer:
471 days
Explanation:
Capacity of Carvins Cove water reservoir = 3.2 billion gallons i.e. 3.2 x 10˄9 gallons
As,
1 gallon = 0.133 cubic feet (cf)
Therefore,
Capacity of Carvins Cove water reservoir in cf = 3.2 x 10˄9 x 0.133
= 4.28 x 10˄8
Applying Mass balance i.e
Accumulation = Mass In - Mass out (Eq. 01)
Here
Mass In = 0.5 cfs
Mass out = 11 cfs
Putting values in (Eq. 01)
Accumulation = 0.5 - 11
= - 10.5 cfs
Negative accumulation shows that reservoir is depleting i.e. at a rate of 10.5 cubic feet per second.
Converting depletion of reservoir in cubic feet per hour = 10.5 x 3600
= 37,800
Converting depletion of reservoir in cubic feet per day = 37, 800 x 24
= 907,200
i.e. 907,200 cubic feet volume is being depleted in days = 1 day
1 cubic feet volume is being depleted in days = 1/907,200 day
4.28 x 10˄8 cubic feet volume will deplete in days = (4.28 x 10˄8) x 1/907,200
= 471 Days.
Hence in case of continuous drought reservoir will last for 471 days before dry-up.
