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jonny [76]
3 years ago
12

For a 20 ohm resistor R, the current i = 2 A. What is the voltage V? Submit your answer as a number without units. ​

Engineering
1 answer:
svetoff [14.1K]3 years ago
7 0

Answer:

20*2=40

Explanation:

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how to calculate the torque when a force is applied on a cog? explain the step-by-step and provide an illustration/diagram. Can
yawa3891 [41]

Explanation:

Torque is the cross product of the radius vector and force vector:

τ = r × F

In other words, it is equal to the radius times the perpendicular component of the force.

τ = r · Ftangential

If we call θ the angle between the radius and the force, then:

τ = r · F sin θ

3 0
3 years ago
Name 3 ways in which robots have improved since the Ebola outbreak.
Ostrovityanka [42]

Answer:

1. They have less malfunctions

2. They can be operated from afar

3. Some are self-operated.

Explanation:

4 0
2 years ago
Determine the reactor volume (assume a CSTR activated sludge aerobic reactor at steady state) required to treat 5 MGD of domesti
12345 [234]

Answer:

1.0MG

Explanation:

to solve this problem we use this formula

S₀-S/t = ksx --- (1)

the values have been given as

concentration = S₀ = 250mg

effluent concentration = S= 10mg

value of K = 0.04L/day

x = 3000 mg

when we put these values into this equation,

250-10/t = 0.04x10x3000

240/t = 1200

we cross multiply from this stage

240 = 1200t

t = 240/1200

t = 0.2

remember the question says that 5MGD is required to be treated

so the volume would be

v = 0.2x5

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4 0
2 years ago
Examine a process whereby air at 300 K, 100 kPa is compressed in a piston/cylinder arrangement to 600 kPa. Assume the process is
professor190 [17]

Answer:

See attachment and explanation.

Explanation:

- The following question can be solved better with the help of a MATLAB program as follows. The code is given in the attachment.

- The plot of the graph is given in attachment.

- The code covers the entire spectrum of the poly-tropic range ( 1.2 - 1.6 ) and 20 steps ( cases ) have been plotted and compared in the attached plot.

3 0
3 years ago
A 3.52 kg steel ball is tossed upward from a height of 6.93 meters above the floor with a vertical velocity of 2.99 m/s. What is
Dafna1 [17]

Answer : The final velocity of the ball is, 12.03 m/s

Explanation :

By the 3rd equation of motion,

v^2-u^2=2as

where,

s = distance covered by the object = 6.93 m

u = initial velocity  = 2.99 m/s

v = final velocity = ?

a = acceleration = 9.8m/s^2

Now put all the given values in the above equation, we get the final velocity of the ball.

v^2-(2.99m/s)^2=2\times (9.8m/s^2)\times (6.93m)

v=12.03m/s

Thus, the final velocity of the ball is, 12.03 m/s

7 0
3 years ago
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