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yarga [219]
3 years ago
15

Find the difference. (-2ab-2a-5) - (6ab+2)

Mathematics
1 answer:
9966 [12]3 years ago
4 0

Answer:

-8ab - 2a - 7

Step-by-step explanation:

Since you're subtracting/adding I like taking away the parentheses which makes the equation: -2ab - 2a - 5 - 6ab - 2

You combine like terms and get:

-8ab - 2a - 7

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Kylie plays softball on the merrick valley team she hits one out of every six balls pitched to her.if 32 balls have been pitched
Ganezh [65]
If 32 is divided by 6, the answer is 5.3. However because she cannot hit part of a ball, the number would be 5. Therefore, she would hit 5 out of 32 balls. 
3 0
3 years ago
1. Suppose that you are watching the tree warden trim branches from a large tree in your yard. He has climbed up 15 meters and h
RSB [31]
In item# 1, we are only given with the height of the tree a=15 meters and we are asked to solve for the hypotenuse. Since we are not given with angle created between the rope the ground level we will assign it as ∠A = ∅
Solving for the length of the rope, we have
sin A = 15/Length of rope
Length of rope = 15 meters / sin A

In item#2, assuming that it is a right triangle we have:
8 ²= x²+3.5²
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The smallest angle:
sin Z =3.5/8
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7 0
3 years ago
A 4:1 scale drawing of a bearing is shown on an A-size print. Using a ruler, you measure the inside diameter of the part on the
Pani-rosa [81]

Answer:

A. 6.0

Step-by-step explanation:

We have been given that the the inside diameter of the part on the paper is 1.50 inches.

We have been given that scale is 4:1 for actual size to drawing side.

\text{Scale}=\frac{\text{Actual size}}{\text{Map size}}=\frac{4}{1}

Upon substituting 1.50 in our given proportion, we will get:

\frac{\text{Actual size}}{1.50\text{ inches}}=\frac{4}{1}

\frac{\text{Actual size}}{1.50\text{inches}}\times 1.50\text{ inches}=\frac{4}{1}\times 1.50\text{ inches}

\text{Actual size}=4\times 1.50\text{ inches}

\text{Actual size}=6.0\text{ inches}

Therefore, the actual size is 6.0 inches and option A is the correct choice.

4 0
3 years ago
Can anybody help me pls
kotegsom [21]
Answer is C

factor the quadratic and get (x+8)(x-1)=0
then use the 0 product property
5 0
3 years ago
Read 2 more answers
How do i solve for x?
mrs_skeptik [129]
The triangles are similar so ∆JKL is just an enlargement of ∆WVU. Therefore the ratios of the side lengths are the same. 10:20 = 1:2 so the side lengths for ∆JKL must be in the ratio 1:2. 15 × 2 = 6x so 30 = 6x so x = 5
4 0
3 years ago
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