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marysya [2.9K]
3 years ago
12

How are magnetic forces like electric forces? (4 points) Select one: a. They both have charges b. In both, opposites attract. c.

In both, opposites repel. d. Neither have charges.
Physics
1 answer:
nlexa [21]3 years ago
6 0

Lets take it down a notch and break it down:

Magnetic forces and electric forces are quite similar, lets take a look at the answers possible:

A. They both have charges

False, magnetic forces do not HAVE charges, but they have an EFFECT on moving charges (that are creating a magnetic field around them).

Why? Electrical forces have positive and negative charges while magnetic forces have a north and south POLE. These two are different forces, therefore magnetic forces do not HAVE charges.

B. In both, opposites attract

We all know opposite poles attract, like poles, don't attract (repelling force). This is true for the magnetic force, now, the electric force, two positively charged particles will exert a repulsive force on one another. DING DING. We have a winner. <u>B is TRUE.</u>

C. In both, opposites repel

False, we already know in electric and magnetic forces that opposites attract and similar charges/poles repel.

D. Neither have charges

False, this is a joke question right? Don't even look at this one!!!!!!!!!


<u>Therefore, </u><u>B</u><u>, is the only true answer that describes how magnetic and electric forces are similar. </u>

Have a nice day!

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_{Z}^{A}X \to _{Z+1}^{A}Y + e^- + \bar{\nu_e}

where e^- its the electron, and \bar{\nu_e} the electronic antineutrino . We can see that the atomic number increases by one (cause a proton it produced and retained into the nucleus), and the atomic mass is approximately the same (there is a small difference between the neutron and proton mass, but its very small).

So, Phosphorus-32 (atomic number 15) will turn to an element with atomic number 16, and atomic mass 32, as:

_{15}^{32}P \to _{15+1}^{32}Y + e^- + \bar{\nu_e}.

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Answer:

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F = 1/4πε₀(q₁q₂)/d²........................ Equation 1

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<em>When d = 1/4 m, q₁q₂ = 1/9×10⁹  C² and 1/4πε₀ = 9×10⁹ Nm²/C²</em>

<em>Substituting these values into equation 1</em>

<em>F =  9×10⁹×1/9×10⁹ /(1/4)²</em>

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<em>F = 16 N</em>

<em>Therefore the force on each charge = 16 N</em>

<em />

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