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aniked [119]
2 years ago
10

Mrs. Walker has on new shoes! When she walks down the waxed hall floors she slips and slides. What could Mrs. Walker do to help

her from slipping on the slick waxed floors at school?
Physics
1 answer:
givi [52]2 years ago
3 0
She could choose to wear shoes designed to have more friction on the bottom, so she won’t slip as easily... (or she could get like a walker or something to hold onto if she really wanted to show off her new shoes)
Hope this helps x
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A spring that has a spring constant of 1400 N/m is stretched to a length of 2.5 m. If the normal length of the spring is 1.0 m,
Daniel [21]
The answer is 1575, I just took the Review.<span />
7 0
3 years ago
The 0.15kg baseball has a speed of v=30 m/s just before it is struck by the bat. It then travels along the trajectory shown befo
notka56 [123]

The magnitude of the average impulsive force imparted to the ball if it is in contact with the bat is 6000 N

The mass of the baseball, m = 0.15 kg

The speed at which it moves, v = 30 m/s

Time at which the baseball was in contact with the bat, t = 0.75 ms

t = 0.75/1000 s

t  = 0.00075 s

The impulsive force is given by the formula:

F=\frac{mv}{t}

Substitute m = 0.15 kg, v = 30, and t = 0.00075s into the formula above:

F=\frac{0.15 \times 30}{0.00075} \\\\F=6000N

The magnitude of the average impulsive force imparted to the ball if it is in contact with the bat is 6000 N

Learn more here: brainly.com/question/25892144

4 0
2 years ago
A scientific study is repeated by four different groups. Only two groups get the same results. Are the data reproducible?
tangare [24]
No, one more group must get the same result as the other group. This will make it more reliable and reproducible.
4 0
2 years ago
How much work is required to accelerate a proton from rest up to a speed of 0.993 c? Express your answer with the appropriate un
Keith_Richards [23]

Answer:

(a). The work done is 7001 MeV.

(b). The momentum of this proton is 4.20\times10^{8}\ kg-m/s.

Explanation:

Given that,

Speed = 0.993 c

We need to calculate the work done

Using work energy theorem

The work done is equal to the kinetic energy relative to the proton

W=K.E

W=\dfrac{m_{p}c^2}{\sqrt{1-\dfrac{v^2}{c^2}}}-m_{p}c^2

Put the value into the formula

W=\dfrac{1.67\times10^{-27}\times(3\times10^{8})^2}{\sqrt{1-(\dfrac{0.993c}{c})^2}}-1.67\times10^{-27}\times(3\times10^{8})^2

W=\dfrac{1.67\times10^{-27}\times(3\times10^{8})^2}{\sqrt{1-(0.993)^2}}-1.67\times10^{-27}\times(3\times10^{8})^2

W=1.122\times10^{-9}\ J

W=7001\ MeV

(b). We need to calculate  the momentum of this proton

Using formula of momentum

p=\dfrac{m_{0}v}{\sqrt{1-\dfrac{v^2}{c^2}}}

Put the value into the formula

p=\dfrac{1.67\times10^{-27}\times0.993c}{\sqrt{1-(\dfrac{0.993c}{c})^2}}

p=\dfrac{1.67\times10^{-27}\times0.993c}{\sqrt{1-(0.993)^2}}

p=1.404\times10^{-26}c

p=4.20\times10^{8}\ kg-m/s

Hence, (a). The work done is 7001 MeV.

(b). The momentum of this proton is 4.20\times10^{8}\ kg-m/s.

4 0
3 years ago
Drawing Conclusions Suppose you take a short piece of wire that is not attached to anything and move it up and down in a magneti
Ulleksa [173]

Answer: No. Circuit should be closed.

Explanation:

A changing magnetic field induces emf in a circuit which is placed in it. This induced emf causes current to flow through it. This is given by Faraday's law which states that induced emf results due to rate of change of magnetic flux.

e = \frac{-d\phi}{dt}= -\frac {dB A} {dt}

Current flows only through a closed circuit. Thus, when a wire is moved up and down in a magnetic field, it will not induce emf because the wire does not form a loop. It is an open circuit.

4 0
3 years ago
Read 2 more answers
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