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aniked [119]
3 years ago
10

Mrs. Walker has on new shoes! When she walks down the waxed hall floors she slips and slides. What could Mrs. Walker do to help

her from slipping on the slick waxed floors at school?
Physics
1 answer:
givi [52]3 years ago
3 0
She could choose to wear shoes designed to have more friction on the bottom, so she won’t slip as easily... (or she could get like a walker or something to hold onto if she really wanted to show off her new shoes)
Hope this helps x
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What electrons are in “motion”, what do you have?
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Why is it important to select a coordinate system when studying motion?
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3 years ago
Two point charges are separated by 10 cm, with an attractive force between them of 15 N. Find the force between them when they a
suter [353]

Answer:

(a) the force is 8.876 N

(b) the magnitude of each charge is 4.085 μC

Explanation:

Part (a)

Given;

coulomb's constant, K = 8.99 x 10⁹ N.m²/C²

distance between two charges, r = 10 cm = 0.1 m

force between the two charges, F = 15 N

when the distance between the charges changes to 13 cm (0.13 m)

force between the two charges, F = ?

Apply Coulomb's law;

F = \frac{Kq_1q_2}{r^2} \\\\let \ Kq_1q_2 = C\\\\F =\frac{C}{r^2} \\\\C = Fr^2\\\\F_1r_1^2 = F_2r_2^2\\\\F_2 =\frac{F_1r_1^2}{r_2^2} \\\\F_2 = \frac{15*0.1^2}{0.13^2} \\\\F_2 = 8.876 \ N

Part (b)

the magnitude of each charge, if they have equal magnitude

F = \frac{KQ^2}{r^2}

where;

F is the force between the charges

K is Coulomb's constant

Q is the charge

r is the distance between the charges

F = \frac{KQ^2}{r^2} \\\\Q = \sqrt{\frac{Fr^2}{K} } \\\\Q =  \sqrt{\frac{15*(0.1)^2}{8.99*10^9} } = 4.085 *10^{-6} \ C\\\\Q = 4.085 \ \mu C

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It is easier to push an empty shopping cart than a full one, because the full shopping cart has more mass than the empty one. Th
Katarina [22]

Answer:

i think its the 2nd law

Explanation:

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Hope this answer help u!!!!

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