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strojnjashka [21]
3 years ago
14

Please help! this is timed!

Physics
2 answers:
sweet-ann [11.9K]3 years ago
7 0
Im pretty sure it is the first answer
Alik [6]3 years ago
5 0

Answer:

I'm positive that it is the first one. Sorry if it wrong.

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Read 2 more answers
A car travels along a horizontal road which is an arc of radius 125m. the greatest speed at which the car can travel without sle
hammer [34]

The coefficient of friction between the Tyre and the ground is 0.11

<u>Explanation:</u>

Given:

Radius of the track (r)=125 m.

Speed with which the car travels (v) =42 km/hr

                                                             =11.67 m/s

To Find:

Coefficient of friction between the Tyre and the ground.

Formula to be used:

Centripetal\ force\ Fc= mv^2/r\\\\=m\times 11.67^2/125\\\\=1.08 m

We know that,Frictional force is equal to centripetal force

Frictional force=μmg

therefore 1.08 m=μmg

Cancelling "m" on both sides we get,

μ=1.08/g=1.08/9.8

=0.11

Thus the coefficient of friction between the Tyre and the ground is 0.11

7 0
3 years ago
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