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strojnjashka [21]
3 years ago
14

Please help! this is timed!

Physics
2 answers:
sweet-ann [11.9K]3 years ago
7 0
Im pretty sure it is the first answer
Alik [6]3 years ago
5 0

Answer:

I'm positive that it is the first one. Sorry if it wrong.

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The weight of a standard object defined as having a mass of exactly 2.9 kg is measured to be 28.449 n. in the same laboratory, a
PtichkaEL [24]
Mass of the object m = 2.9 kg 
Force F1 = 28.449 N 
F1 = m1 x a => a = F / m => 28.449 / 2.9 => a = 9.81, which is gravitational acceleration. 
In the same lab, a = g = 9.81, second object F2 = 48.7N = m2 x a 
m2 = F2 / a => 48.7 / 9.81 => m2 = 4.96 kg 
Mass of the second object m2 = 4.96 kg
4 0
3 years ago
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Definition: This is a drawing showing the direction and magnitude of all forces acting on a body.
Lisa [10]

Answer:

Free body diagram

5 0
3 years ago
Identify three devices that use Convex lenses.
Yuliya22 [10]
Microscope lenses , glasses for people who can't see faraway as well and  microwave lenses which reflect electromagnetic radiation. Oh and curved mirrors.  
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3 years ago
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1 - A submarine has a circular porthole with a radius of 0.10 m. If a force of more than 2x106 N is applied, the porthole will f
S_A_V [24]

In order to solve this problem, it is necessary to apply the concepts related to the Pressure according to the Force and the Area as well as to the pressure depending on the density, gravity and height.

In the first instance we know that the pressure can be defined as

P = \frac{F}{A}

Where

F= Force

A =  Mass

In the second instance the pressure can also be defined as

P = \rho gh

Where,

\rho=Density of Fluid at this case Water

g = Gravitational Acceleration

h = Height

If we develop the problem to find the pressure then,

P = \frac{F}{A}

P = \frac{F}{\pi r^2}

P = \frac{2*10^6}{\pi (0.1)^2}

P = 6.37*10^{7} Pa

Through the second equation we can find the depth to which it can be submerged,

P = \rho gh

Re-arrange to find h

h = \frac{P}{\rho g}

h = \frac{6.37*10^{7}}{1000*9.8}

h = 6499.4m

8 0
3 years ago
Isolating a variable in two equations is easiest when one of them has a coefficient of 1. Let's say we have the two equations 3A
xxTIMURxx [149]

Answer:

B=3A-5

Explanation:

<u>Variable Isolation</u>

It's a common practice when dealing with equations that we have to isolate one variable in terms of other variables and/or constants. The isolation of the variable usually implies adding, subtracting, multiplying or dividing by constants. The following example shows how to isolate the A:

2A+3B=-4\\\\2A=-4-3B\\\\\displaystyle A=\frac{-4-3B}{2}

We are required to find the equation where the variable has a coefficient of 1 and isolate it. The following equation fits into the description:

3A-B=5

Isolating B:

B=3A-5

3 0
3 years ago
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