Mass of the object m = 2.9 kg
Force F1 = 28.449 N
F1 = m1 x a => a = F / m => 28.449 / 2.9 => a = 9.81, which is gravitational acceleration.
In the same lab, a = g = 9.81, second object F2 = 48.7N = m2 x a
m2 = F2 / a => 48.7 / 9.81 => m2 = 4.96 kg
Mass of the second object m2 = 4.96 kg
Microscope lenses , glasses for people who can't see faraway as well and microwave lenses which reflect electromagnetic radiation. Oh and curved mirrors.
In order to solve this problem, it is necessary to apply the concepts related to the Pressure according to the Force and the Area as well as to the pressure depending on the density, gravity and height.
In the first instance we know that the pressure can be defined as

Where
F= Force
A = Mass
In the second instance the pressure can also be defined as

Where,
Density of Fluid at this case Water
g = Gravitational Acceleration
h = Height
If we develop the problem to find the pressure then,




Through the second equation we can find the depth to which it can be submerged,

Re-arrange to find h



Answer:

Explanation:
<u>Variable Isolation</u>
It's a common practice when dealing with equations that we have to isolate one variable in terms of other variables and/or constants. The isolation of the variable usually implies adding, subtracting, multiplying or dividing by constants. The following example shows how to isolate the A:

We are required to find the equation where the variable has a coefficient of 1 and isolate it. The following equation fits into the description:

Isolating B:
