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DaniilM [7]
3 years ago
9

Initially, a particular sample has a total mass of 200 grams and contains 128 x 1010 radioactive nuclei. These radioactive nucle

i have a half life of 1 hour. (a) After 3 hours, how many of these radioactive nuclei remain in the sample (that is, how many have not yet experienced a radioactive decay)
Chemistry
1 answer:
lubasha [3.4K]3 years ago
8 0

Explanation:

Formula to calculate how many particles are left is as follows.

              N = N_{0} (\frac{1}{2})^{l}

where,     N_{0} = number of initial particles

                              l = number of half lives

As it is given that number of initial particles is 128 \times 10^{10} and number of half-lives is 3.

Hence, putting the given values into the above equation as follows.

               N = N_{0} (\frac{1}{2})^{l}

                    = 128 \times 10^{10}(\frac{1}{2})^{3}

                    = 16 \times 10^{10}

or,                    1.6 \times 10^{11}

Thus, we can conclude that 1.6 \times 10^{11} particles of radioactive nuclei remain in the given sample.

In five hours we've gone through 5 half lives so the answer is:

particles

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Answer:

3.0 moles Al₂O₃

Explanation:

We do not know which of the reactants is the limiting reactant. Therefore, you need to convert both of the given mole values into the product. This can be done using the mole-to-mole ratio made up of the balanced equation coefficients.

4 Al + 3 O₂ -----> 2 Al₂O₃

6.0 moles Al            2 moles Al₂O₃
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As you can see, O₂ produces the smaller amount of product. This means O₂ is the limiting reactant. Remember, the limiting reactant is the reactant which runs out before the other reactant(s) are completely reacted. As such, the actual amount of Al₂O₃ produced is 2.7 moles.

However, since this problem is directly addressing how much Al₂O₃ is produced from Al, the answer you most likely are looking for is 3.0 moles Al₂O₃.

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