I hope this helps you
square one side a
Area=a.a
49=a.a
7.7=a.a
a=7
Perimeter=4a=4.7=28
Let
x-------> the length of the base of triangle
y-------> the height of the triangle
we know that
the area of the triangle is equal to
in this problem we have
so
--------> equation 
--------> equation 
Substitute equation in equation
![\frac{1}{2}x[2x+4]\leq 168](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7Dx%5B2x%2B4%5D%5Cleq%20168)
therefore
<u>the answer is</u>
The inequality that can be used to find the possible lengths, x, of the base of the triangle is or
Answer:
it's a little bit confusing and not too clear but the third one should be correct
Wow ! Now THERE's an incentive ! I'm just glad I got in
early enough so that there's an answer block left open.
If you should happen to glance at these three problems,
you'll notice that they're all the same problem, just with
different numbers. So if somebody showed you how to do
ONE of them, you'd know how to do ALL of them.
1). Markup = 10% of $50 = 0.1 x $50 = $5
Selling price = ($50 + $5) = $55 .
2). Markup = 60% of $80 = 0.6 x $80 = $48
Selling price = ($80 + $48) = $128 .
3). Markup = 25% of $140 = 0.25 x $140 = $35
Selling price = ($140 + $35) = $175 .
Answer:
Perimeter 182 cm, area= 2,028 cm2
Step-by-step explanation:
The perimeter of the given rectangle is
2(6 cm + 8 cm) = 28 cm
The area of the given rectangle is
(6 cm)*(8 cm) = 48 cm^2
The larger rectangle will have a perimeter of
6.5*28 cm = 182 cm
The larger rectangle will have an area of
6.5^2*48 cm^2 = 2028 cm^2 . . . . . note the scale factor is squared for area
The appropriate choice is the 3rd one, ...
Perimeter = 182 cm, area = 2,028 cm^2
