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aleksklad [387]
3 years ago
9

Laura was in India for 3 years now she live in in U.S how many months did Laura live in India

Mathematics
1 answer:
liberstina [14]3 years ago
8 0
Answer:

36 months

Explanation:

There is 12 months in one year so if you do 12 times the number of years she spent in India you will get how much months she spent in India. 12•3=36
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If T(x, y) = (x + 5, y + 6) and Pris the image of P, what is the rule for the translation in which P is the image of P'? T(x, y)
xxTIMURxx [149]

Answer:

The translation is;

T(x,y)=(x-5,y-6)

Explanation:

Given the translation rule;

T(x,y)=(x+5,y+6)

when P' is the image of P.

For the inverse, when P is the image of P', the Translation rule would become;

\begin{gathered} x=x^{\prime}+5 \\ x^{\prime}=x-5 \\ y=y^{\prime}+6 \\ y^{\prime}=y-6 \\ So,\text{ the translation rule becomes;} \\ T(x,y)=(x-5,y-6) \end{gathered}

The translation is;

T(x,y)=(x-5,y-6)

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1 year ago
How do you know 3 ÷180 is smaller than 1​
Diano4ka-milaya [45]

Answer:

Because 180 is bigger than 3 and your trying to divide 180 into 3. Which isn't gonna come out an even number. 0.01666666666 is a lot smaller than 3.

Step-by-step explanation:

Hope this helped!!!

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3 years ago
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Multiply (2x-5)(3x2-4x+2)
WITCHER [35]

Answer:The answer is 183, hope I helped.  

8 0
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Find the length of the base of a square pyramid if the volume is 48 cubic inches and has a height of 9 inches.
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birth weights in norway are normally distributed with a mean of 3570 g and a standard deviation of 500g. if the hospital officia
Svetradugi [14.3K]

Answer:

2630 g

Step-by-step explanation:

From the given information:

Given that:

mean (μ) = 3750 g

Standard deviation (σ) = 500

Suppose the hospital officials demand special treatment with a percentage of  lightest 3% (0.03) for newborn babies;

Then, the weight of birth that differentiates the babies that needed special treatment from those that do not can be computed as follows;

P(Z < z₁) = 0.03

Using the Excel Formula; =NORMSINV(0.03) = -1.88

z₁ = - 1.88

Using the test statistics z₁ formula:

z_1 = \dfrac{X-\mu}{\sigma}

-1.88 = \dfrac{X-3570}{500}

By cross multiply, we have:

-1.88 × 500 = X - 3570

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-X = -3570 + 940

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X = 2630 g

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