1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
LekaFEV [45]
3 years ago
13

Using the simple 16 bit floating point representation from class, what is the result (in Hex) of adding together the floating po

int numbers 0xE1A3 and 0x8A1
Engineering
1 answer:
Ahat [919]3 years ago
3 0

Answer:

0xEA44

Step by Step Explanation:

To find addition in Hex system, let's explain the meaning of characters A to F in Hex systems. A represents 10, B represents 11 ... F represents 15. So,

(E1A3)₁₆ + (8A1)₁₆

E1A3

08A1

Adding from most right side to left ->

  1. 3+1=4
  2. A+A=10+10=20. If we find its remainder i.e. dividing by 16, 4 will be the remainder and 1 will be the whole number i.e. 20=16*<u>1</u>+<u>4</u> this 4 will be written at second place on right side while 1 will be carried out to the left side.
  3. <u>1</u>+1+8=10=A
  4. E+0=14=E

So the number becomes:

<em><u>EA44</u></em>

You might be interested in
a cantilever beam 1.5m long has a square box cross section with the outer width and height being 100mm and a wall thickness of 8
djverab [1.8K]

Answer:

a) 159.07 MPa

b) 10.45 MPa

c) 79.535 MPa

Explanation:

Given data :

length of cantilever beam = 1.5m

outer width and height = 100 mm

wall thickness = 8mm

uniform load carried by beam  along entire length= 6.5 kN/m

concentrated force at free end = 4kN

first we  determine these values :

Mmax = ( 6.5 *(1.5) * (1.5/2) + 4 * 1.5 ) = 13312.5 N.m

Vmax = ( 6.5 * (1.5) + 4 ) = 13750 N

A) determine max bending stress

б = \frac{MC}{I}  =  \frac{13312.5 ( 0.112)}{1/12(0.1^4-0.084^4)}  =  159.07 MPa

B) Determine max transverse shear stress

attached below

   ζ = 10.45 MPa

C) Determine max shear stress in the beam

This occurs at the top of the beam or at the centroidal axis

hence max stress in the beam =  159.07 / 2 = 79.535 MPa  

attached below is the remaining solution

6 0
3 years ago
A normal shock wave takes place during the flow of air at a Mach number of 1.8. The static pressure and temperature of the air u
Darina [25.2K]

Answer:

The pressure upstream and downstream of a shock wave are related as

\frac{P_{1}}{P_{o}}=\frac{2\gamma M^{2}-(\gamma -1)}{\gamma +1}

where,

\gamma= Specific Heat ratio of air

M = Mach number upstream

We know that \gamma _{air}=1.4

Applying values we get

\frac{P_{1}}{100kPa}=\frac{2\times 1.4\times 1.8^{2}-(1.4 -1)}{1.4 +1}\\\\\frac{P_{1}}{100kPa}=3.61\\\\\therefore P_{1}=361.33kPa(Absloute)

Similarly the temperature downstream is obtained by the relation

\frac{T_{1}}{T_{o}}=\frac{[2\gamma M^{2}-(\gamma -1)][(\gamma -1)M^{2}+2]}{(\gamma +1)^{2}M^{2}}

Applying values we get

\frac{T_{1}}{423}=\frac{[2\times 1.4\times 1.8^{2}-(1.4-1)][(1.4-1)1.8^{2}+2]}{(1.4+1)^{2}\times 1.8^{2}}\\\\\therefore \frac{T_{1}}{423}=1.53\\\\\therefore T_{1}=647.85K=374.85^{o}C

The Mach number downstream is obtained by the relation

M_{d}^{2}=\frac{(\gamma -1)M^{2}+2}{2\gamma M^{2}-(\gamma -1)}\\\\\therefore M_{d}^{2}=\frac{(1.40-1)\times 1.8^{2}+2}{2\times1.4\times 1.8^{2}-(1.4-1)}\\\\\therefore M_{d}^{2}=0.38\\\\M_{d}=0.616

3 0
4 years ago
C&amp;A's potato chip filling process has a lower specification limit of 9.5 oz. and an upper specification limit of 10.5 oz. Th
Law Incorporation [45]

Answer:

Process capability index = (USL - LSL)/6Sigma = 1/6(0.3)= 0.56

Answer (a) 0.56

Explanation:

3 0
4 years ago
Calculate the amount of power (in Watts) required to move an object weighing 762 N from point A to point B within 29 seconds. Di
Tresset [83]

Answer:

0.556 Watts

Explanation:

w = Weight of object = 762 N

s = Distance = 5 m

t = Time taken = 29 seconds

a = Acceleration

g = Acceleration due to gravity = 9.81 m/s²

Equation of motion

s=ut+\frac{1}{2}at^2\\\Rightarrow a=\frac{2\times (s-ut)}{t^2}\\\Rightarrow a=\frac{2\times (5-0)}{29^2}=\frac{10}{481}

Mass of the body

m=\frac{w}{g}=\frac{762}{9.81}

Force required to move the body

F=ma\\\Righarrow F=\frac{762}{9.81}\times \frac{10}{481}

Velocity of object

v=u+at\\\Rightarrow v=0+\frac{10}{481}\times 29\\\Rightarrow v=\frac{10}{29}

Power

P=Fv\\\Rightarrow P=\frac{762}{9.81}\times \frac{10}{481}\times \frac{10}{29}=0.556\ W

∴ Amount of power required to move the object is 0.556 Watts

7 0
4 years ago
The resistivity of mercury drops suddenly to zero at a critical temperature, maki mercury a superconductor below that temperatur
seropon [69]

Resistance zero meaning superconductor, so True.

4 0
3 years ago
Other questions:
  • A Carnot heat pump maintains the temperature of a house at 22 C in the winter. On a day when the average outdoor temperature is
    7·1 answer
  • Oil with a density of 850 kg/m3 and kinematic viscosity of 0.00062 m2/s is being discharged by an 8-mm-diameter, 42-m-long horiz
    9·1 answer
  • Historically, the introduction of technology has caused profound changes in the labor market and, temporarily at least, displace
    6·1 answer
  • Air is used as the working fluid in a simple ideal Brayton cycle that has a pressure ratio of 12, a compressor inlet temperature
    8·1 answer
  • All of these are designed to absorb collision energy EXCEPT:
    9·2 answers
  • Which step in the engineering design process most likely broke down in the following scenario?
    11·1 answer
  • How many people made machines
    7·2 answers
  • Which of the following can effect LRO?
    12·1 answer
  • How long would it take a marble to travel down a 15 inch piece of cardboard at a 15 degree angle?
    12·1 answer
  • Find the volume of water displaced and position of center of buoyancy for a wooden block of width 2.5m and of depth 1.5m. When i
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!