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Verdich [7]
4 years ago
6

C&A's potato chip filling process has a lower specification limit of 9.5 oz. and an upper specification limit of 10.5 oz. Th

e standard deviation is 0.2 oz. and the mean is 10 oz. The process capability index for the chip filling process is __________________ (round up to two decimal places).
Engineering
1 answer:
Law Incorporation [45]4 years ago
3 0

Answer:

Process capability index = (USL - LSL)/6Sigma = 1/6(0.3)= 0.56

Answer (a) 0.56

Explanation:

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The human eye, as well as the light-sensitive chemicals on color photographic film, respond differently to light sources with di
jeka57 [31]

Answer:

a) at T = 5800 k  

  band emission = 0.2261

at T = 2900 k

  band emission = 0.0442

b) daylight (d) = 0.50 μm

    Incandescent ( i ) =  1 μm

Explanation:

To Calculate the band emission fractions we will apply the Wien's displacement Law

The ban emission fraction in spectral range λ1 to λ2 at a blackbody temperature T can be expressed as

F ( λ1 - λ2, T ) = F( 0 ----> λ2,T) - F( 0 ----> λ1,T )

<em>Values are gotten from the table named: blackbody radiati</em>on functions

<u>a) Calculate the band emission fractions for the visible region</u>

at T = 5800 k  

  band emission = 0.2261

at T = 2900 k

  band emission = 0.0442

attached below is a detailed solution to the problem

<u>b)calculate wavelength corresponding to the maximum spectral intensity</u>

For daylight ( d ) = 2898 μm *k / 5800 k  = 0.50 μm

For Incandescent ( i ) = 2898 μm *k / 2900 k = 1 μm

3 0
3 years ago
The output voltage of a power supply is normally distributed with mean 12 V and standard deviation 0.11 V. If the upper and lowe
podryga [215]

Answer:

82.62%

Explanation:

The z score is a score used in statistics to determine by how many standard deviations the raw score is above or below the mean. The z score is given by:

z=\frac{x-\mu}{\sigma} \\\\where\ x=raw\ score,\mu=mean\ and\ \sigma=standard\ deviation.\\\\Given \ that\ \mu=12V, \sigma=0.11V.\\\\For\ x11.85V:\\\\z=\frac{11.85-12}{0.11} =-1.36\\\\

From the normal distribution table, P(11.85 < x < 12.15) = P(-1.36 < z < 1.36) = P(z < 1.36) - P(z < -1.36) = 0.9131-0.0869 = 0.8262 = 82.62%

4 0
3 years ago
1) I love to swim. 2) A few years ago, my new year's resolution was to become a faster swimmer. 3) First, I started eating bette
bezimeni [28]
Do you think you could help me on my latest question
5 0
3 years ago
Water is flowing in a metal pipe. The pipe OD (outside diameter) is 61 cm. The pipe length is 120 m. The pipe wall thickness is
Yuki888 [10]

Answer:

1113kN

Explanation:

The ouside diameter OD of the pipe is 61cm and the thickness T is 0.9cm, so the inside diameter ID will be:

Inside Diameter = Outside Diameter - Thickness

Inside Diameter = 61cm - 0.9cm = 60.1cm

Converting this diameter to meters, we have:

60.1cm*\frac{1m}{100cm}=0.601m

This inside diameter is useful to calculate the volume V of water inside the pipe, that is the volume of a cylinder:

V_{water}=\pi  r^{2}h

V_{water}=\pi (\frac{0.601m}{2})^{2}*120m

V_{water}=113.28m^{3}

The problem gives you the water density d as 1.0kg/L, but we need to convert it to proper units, so:

d_{water}=1.0\frac{Kg}{L}*\frac{1L}{1000cm^{3}}*(\frac{100cm}{1m})^{3}

d_{water}=1000\frac{Kg}{m^{3}}

Now, water density is given by the equation d=\frac{m}{V}, where m is the water mass and V is the water volume. Solving the equation for water mass and replacing the values we have:

m_{water}=d_{water}.V_{water}

m_{water}=1000\frac{Kg}{mx^{3}}*113.28m^{3}

m_{water}=113280Kg

With the water mass we can find the weight of water:

w_{water}=m_{water} *g

w_{water}=113280kg*9.8\frac{m}{s^{2}}

w_{water}=1110144N

Finally we find the total weight add up the weight of the water and the weight of the pipe,so:

w_{total}=w_{water}+w_{pipe}

w_{total}=1110144N+2500N

w_{total}=1112644N

Converting this total weight to kN, we have:

1112644N*\frac{0.001kN}{1N}=1113kN

7 0
3 years ago
Two or more parts put together is called<br> What is this
Delicious77 [7]

Answer:

compound

Explanation:

8 0
3 years ago
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