Answer:
x = 28
Step-by-step explanation:
If AB and CD are the straight lines, sum all the angles formed at a point lying on this line will be 180°.
m∠COE + m∠EOF + m∠FOB + m∠BOD = 180° [Angles at a point O on line AB]
3x + x + (x + 12) + m∠BOD = 180°
m∠BOD = 180° - (5x + 12)
Similarly, m∠AOD + m∠AOC = 180°
152° + m∠AOC = 180°
m∠AOC = 28°
Since, ∠AOC and ∠BOD are the vertical angles,
m∠AOC = m∠BOD
180° - (5x + 12)° = 28°
5x + 12 = 180 - 28
5x = 140
x = 28
Given:ABCD is a rhombus.
To prove:DE congruent to BE.
In rombus, we know opposite angle are equal.
so, angle DCB = angle BAD
SINCE, ANGLE DCB= BAD
SO, In triangle DCA
angle DCA=angle DAC
similarly, In triangle ABC
angle BAC=angle BCA
since angle BCD=angle BAD
Therefore, angle DAC =angle CAB
so, opposite sides of equal angle are always equal.
so,sides DC=BC
Now, In triangle DEC and in triangle BEC
1. .DC=BC (from above)............(S)
2ANGLE CED=ANGLE CEB (DC=BC)....(A)
3.CE=CE (common sides)(S)
Therefore,DE is congruent to BE (from S.A.S axiom)
Answer:
it is the second one
Step-by-step explanation:
Michael bought 3.5 lbs of cheese
Divide 11.48 by 3.28
Answer:
K = 50
L = 90
KML = 40
LMN = 140
Step-by-step explanation:
The sum of the angles in a triangle will always be 180 degrees, and in the triangle pictured, we know the value of each angle. We can say that
5x + 4x + 9x = 180
18x = 180
x = 10
Now that we know the value of x, we can figure out the value of the angles.
K = 5x = 50
L = 9x = 90
KML = 4x = 40
A straight line is 180 degrees, so to find angle KMN, you have to subtract KML (4x) from 180
180 - 4x = 180 - 40 = 140
