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3 years ago

In the sequence below, a, = 9. Which of the following would be the correct way to label the 3 in the

Mathematics

1 answer:

zysi [14]3 years ago

8 0

Answer:

Step-by-step explanation:3,9,27,81 because this is multiplication

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What value of x is in the solution set of 3(x – 4) = 5x + 2?<br> -10

timurjin [86]

Answer:

x = - 7

Step-by-step explanation:

Given

3(x - 4) = 5x + 2 ← distribute left side

3x - 12 = 5x + 2 ( subtract 5x from both sides )

- 2x - 12 = 2 ( add 12 to both sides )

- 2x = 14 ( divide both sides by - 2 )

x = - 7

6 0

3 years ago

5.4+ 3(52-15 +2)<br> What is it

iragen [17]

Answer:

122.4

Step-by-step explanation:

Remember PEMDAS

Parentheses

Exponents

Multiply

Divide

Add

Subtract

(52-15+2)=39

39x3=117

117+5.4=122.4

3 0

3 years ago

Read 2 more answers

a package of 8 rechargeable batteries cost 12. at the rate how much would 20 rechargeable batteries would cost

Anettt [7]

Step-by-step explanation:

8 battery =12

20 battery =?(x)

8x=240

x=240÷8

x=30

for 20 battery..it would cost 30

5 0

3 years ago

Please answer correctly !!!!!!!!! Will<br> Mark brainliest !!!!!!!!!!!!!

il63 [147K]

Answer:

$x=-\frac{-20+\sqrt{-20w+3600}}{10},\:x=-\frac{-20-\sqrt{-20w+3600}}{10}$

Step-by-step explanation:

$w=-5\left(x-8\right)\left(x+4\right)\\\mathrm{Expand\:}-5\left(x-8\right)\left(x+4\right):\quad -5x^2+20x+160\\w=-5x^2+20x+160\\Switch\:sides\\-5x^2+20x+160=w\\\mathrm{Subtract\:}w\mathrm{\:from\:both\:sides}\\-5x^2+20x+160-w=w-w\\Simplify\\-5x^2+20x+160-w=0\\Solve\:with\:the\:quadratic\:formula\\\mathrm{Quadratic\:Equation\:Formula:}\\\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\mathrm{For\:}\quad a=-5,\:b=20,\:c=160-w:\quad x_{1,\:2}=\frac{-20\pm \sqrt{20^2-4\left(-5\right)\left(160-w\right)}}{2\left(-5\right)}\\x=\frac{-20+\sqrt{20^2-4\left(-5\right)\left(160-w\right)}}{2\left(-5\right)}:\quad -\frac{-20+\sqrt{-20w+3600}}{10}\\x=\frac{-20-\sqrt{20^2-4\left(-5\right)\left(160-w\right)}}{2\left(-5\right)}:\quad -\frac{-20-\sqrt{-20w+3600}}{10}\\The\:solutions\:to\:the\:quadratic\:equation\:are\\x=-\frac{-20+\sqrt{-20w+3600}}{10},\:x=-\frac{-20-\sqrt{-20w+3600}}{10}$

6 0

3 years ago

Find the volume of a sphere that has diameter of 9 feet.

jek_recluse [69]

Answer:

V≈381.7ft³

Step-by-step explanation:

try using a sphere calculator next time its a lot easier and saves time

5 0

3 years ago